Download presentation

Presentation is loading. Please wait.

Published byAbigail Rogers Modified over 3 years ago

1
We use inequalities when there is a range of possible answers for a situation. I have to be there in less than 5 minutes, This team needs to score at least a goal to have a chance of winning, To get into the city, I need at most $6.50 for train fare are all examples of situations where a limit is specified, but … I < 5 minutes T 1 goal F $6.50 … a range of possibilities exist beyond that limit. Thats what we are interested in when we study inequalities. linear inequalities in two variables 3.7

2
Sara and Ali want to donate some money to a local food pantry. To raise funds, they are selling necklaces and earrings that they have made themselves. Necklaces cost $8 and earrings cost $5. What is the range of possible sales they could make in order to donate at least $100? amount of money earned from selling earrings + amount of money earned from selling necklaces $100 5y + 8x $100 … The objective of todays lesson is to graph such linear inequalities on the coordinate plane, and determine a solution set

3
Example 1 Graph each inequality x + 2y 4 222 Step1: Put the inequality in slope intercept form: y = mx + b and graph it. 2y -x + 4 b Caution or (solid) (dashed) IF Step2 Select a testing point thats not on the line, substitute it into the inequality. If the result is true, shade that region. Otherwise shade the opposite one. 0 + 2(0) 4 0 4 True … Test (0, 0).. The easiest point

4
Example 2 3x 2(y – 1) 3x 2y – 2 b -2y -3x – 2 Caution or (solid) (dashed) IF -2 Test (0, 0) 0 -2 true … 3(0) 2(0 – 1) 3x 2(y – 1)

5
Example 3 x + 1 < 0 x < – 1 Vertical line through x = – 1 Test (0, 0) False … … so we shade the region that does not contain point (0, 0) x < – 1 0 < – 1

6
Example 4 y – 2 > 0 y > 2 horizontal line through y = 2 Test (0, 0) False … … so we shade the region that does not contain point (0, 0) y > 2 0 > 2

7
Example 5 x + y > 0 y > -x + 0 b Test (-1, -1) False … -1 + (-1) > 0 -2 > 0

8
Written Exercises.. page 138 2) x – 1 < 0

9
4) y + 2 0

10
6) x + y < 0

11
8) x + 2y 0

12
10) x – y < 1

13
Page 138 #s 12, 14, 16, 18 HomeworkHomework

14
12) x + 2y 2

15
14) 2x – 3y < 6

16
16)

17
18) 2(y – 1) > 3(x + 1)

18
Graph each system of inequalities b Test (0, 0) True … 0 0 -1 0 -1 b Test (0, 0) True … 0 0 +2 0 2

19
Page 138 #s 20, 24, 28, 32 HomeworkHomework

20
Graph each system of inequalities b Test (0, 0) True … 0 < 0 + 2 0 < 2 Test (0, 0) False … 0 > 1 23) 1 – y < 0 – y < – 1 y > 1 Horizontal line

21
20)

22
24)

23
28)

24
32)

Similar presentations

OK

Lesson 2.11 Solving Systems of Linear Inequalities Concept: Represent and Solve Systems of Inequalities Graphically EQ: How do I represent the solutions.

Lesson 2.11 Solving Systems of Linear Inequalities Concept: Represent and Solve Systems of Inequalities Graphically EQ: How do I represent the solutions.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on poem song of the rain Ppt on brand building and management Ppt on service oriented architecture Ppt on standing order act fee Ppt on mobile computing from iit bombay Ppt on hydroelectric dams in india Ppt on regular expression builder Ppt on indian textile industries in nigeria Ppt on career options in humanities Ppt on body language