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Algebra I Unit 1: Solving Equations in One Variable.

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Presentation on theme: "Algebra I Unit 1: Solving Equations in One Variable."— Presentation transcript:

1 Algebra I Unit 1: Solving Equations in One Variable

2 Unit 1: Learning Goal 1.4 Students will solve one-, two- and multi-step equations using the properties of real numbers and the properties of equality to justify the steps including real-world situations; represent solution process using concrete models.

3 Unit 1: Learning Goal 1.4 – Essential Knowledge and Skills for Students The students will use problem solving, reasoning, communication, connections and representation to: –Using the properties of real numbers and the properties of equality, and solve equations. –Use concrete and pictorial models to represent and solve equations –Justify the steps to the solutions using the properties of real numbers and the properties of equality. –Demonstrate an understanding that equivalent equations have the same solution. –Demonstrate and understanding that adding the same quantity to each side of an equation produces an equivalent equation. –Write equations that represent real-world applications and solve using appropriate methods. –Math/write a verbal statement that describes a given equation.

4 Unit 1: Learning Goal 1.4 Algebra I Standards: EA-4.7, EA-1.3, and EA-1.6 EA-4.7 – Carry out procedures to solve linear equations in one variable algebraically. EA-1.3 – Apply algebraic methods to solve problems in real world contexts. EA-1.6 – Understand how algebraic relationships can be represented in concrete models, pictorial models, and diagrams.

5 Solving Equations by using addition and subtraction

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7 Note: that when you have a term such as – c = -27 such as the one above. The variable actually has a coefficient of -1. Remember that the product of two negative numbers is positive you can multiply each side of the equation by -1 so that your answer is c = 27.

8 Helpful Hints: If the same number is added or subtracted to each side of an equation, then the result is an equivalent equation. Equivalent Equations have the same solution. To Solve an equation means to find all values of the variable that make the equation a true statement. One way to do this is to isolate the variable having a coefficient of 1 on one side of the equation. You can sometimes do this by using the Addition Property of Equality. Isolating Variables – when isolating variables it does not matter whether the variable ends up on the right side or the left side of the equation. For example, the solution of 8 = 15 + z is still -7, even though the final step may be -7 = z.

9 Solving Equations by using addition and subtraction Click here to try and electronically balance equations

10 Solving Equations by using multiplication and division

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12 6y/6 = 54/6 y = 9 -7d/ -7 = -84/-7 d = 12 22b/22 = 176/22 b = 8 2.4f/2.4 = 21.6/2.4 f = 9

13 (-6)(p/-6) = (7/12)(-6) p = -3 1/2 Change – 2 1/3 into – 7/3, which is an improper fraction (-3/7)(-7/3q) = (21)(-3/7) q = -9

14 Solving Multi-Step Equations

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16 10 – 7p = p = p / -7 = -28 / -7 p = r = = r = r / -1.9 = 5.7/-1.9 r = -3

17 Solving Multi-Step Equations (4)- 6 = [(-2n-3)/4](4) -24 = -2n / -2 = - 2n/-2 n = 10 1/2 (5)(t / 5 – 4)= - 10(5) t – 20 = = + 20 t = -30

18 Solving Equations with variable on each side

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20 Steps for solving Equations: Step 1: Use the Distributive Property to remove the grouping symbols. Step 2: Simplify the expressions on each side of the equals sign. Step 3: Use the Addition and/or Subtraction Properties of Equality to get the variables on one side of the equals sign and the numbers without variables on the other side of the equals sign. Step 4: Simplify the expression on each side of the equals sign. Step 5: Use the Multiplication or Division Property of Equality to solve. If the solution results in a false statement, there is no solution of the equation. If the solution results in an identity, the solution is all numbers.

21 Solving Equations with variable on each side 18 = 2n / 2 = 2n /2 n = 13 1/2 + 9 = n = 4n – 9 - 2n = - 2n 1 – 2.7 y = y 1/3.7 = 3.7y/3.7 y = 1/3.7 or y = + 2.7y y = y = - 9

22 Solving Equations with variable on each side 19.4 c – 2.4 = c/19.4 = 8.8/19.4 c = 8.8/19.4 or = c – 2.4 = -8.3c c = c 3 = 12x /12 = 12x/12 x = -5/ = – 4x = 8x x = 4x

23 Work Cited Carter, John A., et. al. Glencoe Mathematics Algebra I. New York: Glencoe/McGraw- Hill, Greenville County Schools Math Curriculum Guide


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