# How Accessible Is Our School ? By: Tiffany Year 8.

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How Accessible Is Our School ? By: Tiffany Year 8

Introduction In this unit we learned about tangent ratios. We learned how to use them in real life, by using trigonometry to calculate height of ramps.

What Did We Do? During this task we needed to work in groups. In my group we measured the total heights, and width of all of the steps. After we had all the information we needed then we started doing the calculation.

What is Trigonometry? Trigonometry is literally the measuring (of angles and sides) of triangles. Hypotenuse (H) Opposite (O) Adjacent (A) Angle X Q: How did they come up with the word Trigonometry? A: The first part of the word is from Greek trigon which is "triangle". The second part of the word is from Greek metry it means "a measure." Know more about Trigonometry!!

Places I Choose The two places I choose were : Steps going in past by the primary library Steps out from the cafeteria

Steps going in past the primary library ( One ) Information: Total height of all steps: 62.3 cm Total width of all steps: 104.8 cm Space available for ramp: 16.6 m ? 62.3cm ? Side Vision Of The Ramp Front Vision Of The Ramp ?=What I need to figure out

Calculation One (Part A) An assisted use wheel chair ramp: The ratio of the height and the bottom length Is 1:6, so the bottom length should be 373.8cm. And the length of the ramp should be 378.955 cm. x = bottom length y = length of ramp 62.3 : x = 1 : 6 y×y = 62.3×62.3+373.8×373.8 1 x = 62.3×6 y×y = 3881.29+139726.44 1 x = 373.8 y×y = 143607.73 x = 373.8÷1 y = 143607^ x = 373.8 y = 378.955

Calculation One (Part B) A ramp that doesn’t need help: The ratio of the height and the bottom length Is 1:12, so the bottom length should be 747.6 cm. And the length of the ramp should be 750.191 cm. x = bottom length 62.3 : x = 1 : 12 1 x = 62.3×12 1 x = 747.6 x = 747.6÷1 x = 747.6 y = length of ramp y×y = 62.3×62.3+747.6×747.6 y×y = 3881.29+558905.76 y×y = 562787 y = 562787^ y = 750.191

Steps out from the cafeteria (Two) Information: Total height of all steps: 28.2 cm Total width of all steps: 62 cm Space available for ramp: 7 m ? ? Side Vision Of The Ramp Front Vision Of The Ramp ?=What I need to figure out 28.2 cm

Calculation Two (Part A) An assisted use wheel chair ramp: The ratio of the height and the bottom length Is 1:6, so the bottom length should be 171 cm. And the length of the ramp should be 249.726 cm. x = bottom length 28.2 : x = 1 : 6 1 x = 28.2×6 1 x = 171 x = 171÷1 x = 171 y = length of ramp y×y = 62.3×62.3+171×171 y×y = 3881.29+29241 y×y = 62363.29 y = 62363.29^2 y = 249.726 ?

Calculation Two (Part B) A ramp that doesn’t need help: The ratio of the height and the bottom length Is 1:12, so the bottom length should be 338.4 cm. And the length of the ramp should be 339.597cm. x = bottom length 28.2 : x = 1 : 12 1 x = 28.2×12 1 x = 338.4 x = 338.4÷1 x = 338.4 ? y = length of ramp y×y = 338.4×338.4+28.2×28.2 y×y = 114514.56+812.16 y×y = 115326.72 y = 115326.72^ y = 339.597

Reflection In this task I used trigonometry to help me calculate the length of the ramps. I used trigonometry because it was very useful and simple. I found that trigonometry could be use in real life. And learned that mathematics can help us a lot in our life’s.

Suggestions I think that we could add elevators to make the school more accessible. Why have I suggested elevators instead of ramps? Because we have very steep stairs in our school so I think that we should just add elevators instead, it would be much easier for people who are wheel chair pound.

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