Download presentation

Presentation is loading. Please wait.

Published byHayden Hale Modified over 2 years ago

1
© Boardworks Ltd of 27 These icons indicate that teachers notes or useful web addresses are available in the Notes Page. This icon indicates the slide contains activities created in Flash. These activities are not editable. © Boardworks Ltd of 27 AS-Level Maths: Mechanics 1 for Edexcel M1.2 Vectors in mechanics For more detailed instructions, see the Getting Started presentation.

2
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

3
© Boardworks Ltd of 27 Definition Vectors are quantities that are completely described by a scalar magnitude and a direction. Displacement, velocity, acceleration and force can all be vectors – they can be described fully by their magnitude and direction. Vectors are often represented by a directed line segment. A B A bold letter is used to represent vectors in text books and on exam papers. When writing by hand, the convention is to underline the letter. This vector could be represented as: a, a or AB.

4
© Boardworks Ltd of 27 Column and component form A vector can be represented in component form as a i + b j in two dimensions, or a i + b j + ck in three dimensions. A vector can also be represented in column form as or. b a c b a The vectors i, j and k are unit vectors in the positive directions of the x, y and z axes respectively.

5
© Boardworks Ltd of 27 Position vectors r is often used to denote a position vector. For example, if OA = 3i + 2j – k, we might say r = 3i + 2j – k. The position vector of a point A is the vector OA where O is the origin.

6
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Magnitude of a vector Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

7
© Boardworks Ltd of 27 Magnitude of a vector The magnitude of a vector is the size of the vector. When representing a vector by a directed line segment, the magnitude of the vector is represented by its length. The magnitude of a vector is equal to. a The magnitude of a vector is found using Pythagoras Theorem. a b x If x = a i + b j then = x Similarly, in three dimensions, if x = a i + b j + c k then =

8
© Boardworks Ltd of 27 Magnitude questions Find the magnitude of the following vectors: a) 3i + 2j b) 4i – 6j + k c) -i + 3j – 5k 5 3 d) e)

9
© Boardworks Ltd of 27 Magnitude solutions b) Magnitude = c) Magnitude = d) Magnitude = e) Magnitude = a) Magnitude =

10
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Unit vectors Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

11
© Boardworks Ltd of 27 Unit vectors A unit vector is a vector of magnitude 1. A unit vector in the direction of a given vector is found by dividing the vector by the magnitude: v v v = ˆ If v is a vector then the corresponding unit vector is represented by. v ˆ

12
© Boardworks Ltd of 27 Unit vector questions Find a unit vector in the direction of the following vectors: a) 4i – 2j b) 3i – j + 4k c) –3i + 5j – 2k d) e)

13
© Boardworks Ltd of 27 Unit vector solutions

14
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Multiplying vectors Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

15
© Boardworks Ltd of 27 Multiplication of a vector by a scalar If the scalar is greater than 1, the resulting vector is larger than the original vector and parallel to it. 3(2i – 5j + k) = 6i – 15j + 3k To multiply a vector by a scalar, multiply each component of the vector by the scalar. If the scalar is less than 1, the resulting vector is smaller than the original vector and parallel to it.

16
© Boardworks Ltd of 27 Parallel vectors Two vectors are parallel if one is a scalar multiple of the other: For vectors to be equal, the i, j and k components must be equal. One vector is the negative of another if each of their corresponding components have opposite signs. 3i – 3j + 4k and –9i + 9j – 12k are parallel vectors since –9i + 9j – 12k = –3(3i – 3j+ 4k)

17
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Addition and subtraction of vectors Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

18
© Boardworks Ltd of 27 Addition and subtraction Adding and subtracting vectors in component form is simply a case of adding and subtracting the i, j and k components separately. Add the following vectors: 3i + 5j – k, 2i + 3k and –4i + 3j + k. (3i + 5j – 2k) + (2i + 3k) + (–4i + 3j + k) = i + 8j + 2k

19
© Boardworks Ltd of 27 Triangle law of addition a b Draw the vector representing a + b. To add vectors using the triangle law, one vector is placed on the end of another. The resultant vector is then shown.

20
© Boardworks Ltd of 27 Parallelogram law of addition To add two vectors, a and b, using the parallelogram law, the vectors are first placed so that they both start from the same fixed point. a is then put on the end of b and b is placed at the end of a. A parallelogram is now formed – the diagonal of this is the vector a + b. Draw the vector representing a + b. a b

21
© Boardworks Ltd of 27 Contents © Boardworks Ltd of 27 Examination-style questions Definition of a vector Magnitude of a vector Unit vectors Multiplying vectors Addition and subtraction of vectors Examination-style questions

22
© Boardworks Ltd of 27 A boy swims across a river from a point A on one bank to a point B on the other. A and B are directly opposite each other and the river is 24 metres wide. The river is flowing at 2 ms –1 parallel to the banks. If the boy reaches point B after swimming for 16 seconds, at what speed and in what direction did he swim? Examination-style question 1

23
© Boardworks Ltd of 27 Solution 1 Draw a triangle of velocities: If the river is 24 m wide and it takes 16 seconds to cross, the resultant speed is 1.5 ms –1 (24 16). v 2 = Therefore the boy swims at a speed of 2.5 ms –1 at an angle of 36.9° to the bank. v x°x° v = 2.5 x = 53.1°tan x = 2 1.5

24
© Boardworks Ltd of 27 Examination-style question 2a Two boats A and B are travelling with constant velocities. A travels with a velocity of (2i + 4j) kmh –1 and B travels with a velocity of (–2i + 5j) kmh –1. a) Find the bearings on which A and B are travelling. A is moving in the first quadrant at an angle of tan –1 2 to the horizontal. This is an angle of 63.4° (to 3 s.f.), so A is travelling on a bearing of 027°. B is moving in the second quadrant at an angle of tan –1 2.5 to the horizontal. This is an angle of 68.2° (to 3 s.f.), so B is travelling on a bearing of 338°.

25
© Boardworks Ltd of 27 Examination-style question 2b and c At 2pm, A is at point O and B is 5 km due east of O. At time t hours after 2pm, the position vectors of A and B relative to O are a and b respectively. b) Find a and b in terms of t, i and j. c) At what time will A be due north of B? a = t (2i + 4j) = 2 t i + 4 t j When A is due north of B, the i components are equal. Equating i components gives 2 t = 5 – 2 t 4 t = 5 t = Therefore A is due north of B at 3:15pm. b = 5i + t (–2i + 5j) = (5 – 2 t )i + 5 t j

26
© Boardworks Ltd of 27 Examination-style question 2d At time t hours after 2pm the distance between the two boats is d km. d) Show that d 2 = 17 t 2 – 40 t + 25 The distance between the two boats is AB. d 2 is therefore equal to AB 2. AB = b – a = (5 – 2 t )i – 2 t i + (5 t – 4 t )j = (5 – 4 t )i + t j AB 2 = (5 – 4 t ) 2 + t 2 d 2 = 25 – 40 t + 16 t 2 + t 2 = 17 t 2 – 40 t + 25

27
© Boardworks Ltd of 27 Examination-style question 2e e) At 2pm the boats were 5 km apart. Find, correct to the nearest minute, the time when the boats are again 5 km apart. When the boats are 5 km apart, d 2 = = 2.35 (to 3 s.f.), which is equivalent to 2 hours 21 minutes (to the nearest minute). Therefore, 25 = 17 t 2 – 40 t t 2 – 40t = 0 t (17 t – 40) = 0 t = 0 or t = Therefore the boats are again 5 km apart at 4:21pm.

Similar presentations

© 2016 SlidePlayer.com Inc.

All rights reserved.

Ads by Google