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Balancing Chemical Equations What goes in must come out!

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What is the Law of Conservation of Mass? If 14 grams of N 2 reacted with 3 grams of H 2, how many grams of ammonia would be produced? In the reaction N 2 + 3H 2 2NH 3

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Law of Conservation of Mass Law of Conservation of Mass You need to remember this law! The Law of Conservation of Mass states: that mass is neither created nor destroyed in any chemical reaction. Therefore balancing of equations requires the same number of atoms on both sides of a chemical reaction. The number of atoms in the Reactants must equal the Number of atoms in the Products

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Do these reactions abide by the Law of Conservation of Mass?

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Balancing Chemical Equations Balancing a chemical equation is much like the work of an accountant who has to show every penny that comes in and where it has gone to.

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In order to balance equations, we first must remember…. How to count atoms! C atoms= 1 O atoms= 2 C atoms= 6 O atoms= 6 x 2= 12 Mg atoms= 8 N atoms= 8 x 1 x 2= 16 O atoms= 8 x 3 x 2= 48

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Practice Problems #2a-e! Git er done!

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How many of each? a. 2Na + 2H 2 O 2NaOH + H 2 ReactantsProducts Na H O Balanced? ___Yes ___No

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How many of each? c. NaCl + F 2 NaF +Cl 2 ReactantsProducts Na Cl F Balanced? ___Yes ___No

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Practice Problems #3a-e

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Balancing Equations ___ Al(s) + ___ Br 2 (l) ---> ___ Al 2 Br 6 (s) 23

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Balancing Equations Try this one! ___ CH 4 + ___ O 2 ---> ___ CO 2 + ___H 2 O

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CH 4 + 2O 2 ---> CO 2 + 2H 2 O

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[1] Just count up the atoms on each side Mg + O 2 MgO Mg O [2] The numbers aren’t balanced so then add “BIG” numbers to make up for any shortages And adjust totals Mg + O 2 MgO Mg O

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Mg + O 2 MgO Mg O But the numbers still aren’t equal, so add another “BIG” number 2 And adjust totals again NOW BOTH SIDES HAVE EQUAL NUMBERS OF ATOMS WE SAY THAT THE EQUATION IS BALANCED!! 2

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Try to balance these equations on WS D.6(p.4 of your packet) using the same method: [1] H 2 + O 2 H 2 O [3] Ca + H 2 O Ca(OH) 2 + H 2 [2] Mg + O 2 MgO

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Try to balance these equations on WS D.6(p.4 of your packet) using the same method: [1] 2H 2 + O 2 2H 2 O [3] Ca + 2H 2 O Ca(OH) 2 + H 2 [2] 2Mg + O 2 2MgO

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Steps to Balance Equations: Balance elements that appear only once on each side of the arrow. Next balance elements that appear only once on each side but have different numbers of atoms. Finally balance elements that are in two formulas in the same side.

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Example NH 3 + O 2 NO + H 2 O Reactants Products N appears once on both sides in equal numbers, so the coefficient for NH 3 is the same as for NO.

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Example: NH 3 + O2 NO + H 2 O Next look at H which appears only once on each side but has different numbers of atoms, 3 on the left and 2 on the right. The least common multiple of 3 and 2 is 6, so rewrite the equation to get 6 atoms of H on both sides: 2NH 3 + O 2 NO + 3H 2 O

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Example: 2NH 3 + O2 NO + 3H 2 O There are 2 oxygen atoms on the left and 5 on the right — the least common multiple of 2 and 5 is 10, so rewrite the equation as: 2NH 3 + 5O 2 4NO + 6H 2 O

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Now count the atoms on each side: 2NH3 + 5O2 4NO + 6H2O Write them out keeping them on the appropriate side of the chemical equation 2 N (nitrogen atoms) 4 N (nitrogen atoms) 6 H (hydrogen atoms) 12 H (hydrogen atoms) 10 O (oxygen atoms) 10 O (oxygen atoms) “YET” This shows the equation not to be balanced “YET”

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Check the number again: If you double the N and H on the left the equation will be balanced: 4NH3 + 5O2 4NO + 6H2O

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Double-check: 4NH3 + 5O2 4NO + 6H2O 4 N (nitrogen atoms) 4 N (nitrogen atoms) 12 H (hydrogen atoms) 12 H (hydrogen atoms) 10 O (oxygen atoms) 10 O (oxygen atoms) The equation is Balanced

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