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Singlefibre optics at LONAP Will Hargrave RIPE68 EIX^W connect-bof 2014-05-15
New product: 1000BX / 10G-BX
Delivering 1G or 10G service over a single strand of singlemode fibre Easy to upgrade 1G->2G, 10G->20G Saves LONAP ODF space Save crossconnect fees! No need to swap TX/RX Available since Jan-2014
New product: 1000BX / 10G-BX Downsides include: – ‘weird’ optic type – confusion – slight cost increase So we expect this will mainly be used by smaller ‘clued-up’ members
Interface description: 1000Base-BX “downstream 1000Base-BX–D” TX: 1310nm RX: 1490nm Flexoptix order code: S.B1612.10.CLDL Cisco: GLC-BX-U (other vendors are available) Juniper: 1000Base-BX10-U 13/14 Cost approx 45EUR per transceiver
Interface description: 10GBase-BX “downstream” TX: 1270nm RX: 1330nm Flexoptix order code: (other vendors are available) – SFP+: P.B1696.10.AD – XFP: X.B1696.10.DA Cost approx 350EUR per transceiver
Questions? Will Hargrave firstname.lastname@example.org
Addition 1’s to
Addition Facts = = =
( ) ax 2 + bx + c 2x x + 5 ac b 2(5) =10 = (2x + 1)(x + 5) check it by foiling 2x x+ 1x+ 5 2x(x + 5 ) + 1(x + 5)
WEEK 1 You have 10 seconds to name…
Slide 1 Insert your own content. Slide 2 Insert your own content.
ADDING INTEGERS 1. POS. + POS. = POS. 2. NEG. + NEG. = NEG. 3. POS. + NEG. OR NEG. + POS. SUBTRACT TAKE SIGN OF BIGGER ABSOLUTE VALUE.
X-box Factoring. X- Box 3-9 Product Sum Factor the x-box way Example: Factor 3x 2 -13x (3)(-10)= x 2x 3x 2 x-5 3x +2.
Bottoms Up Factoring. Start with the X-box 3-9 Product Sum
Bell Schedules Club Time is available from 8:05-8:20 1 st 8:20 – 9:15 2 nd 9:20 – 10:10 3 rd 10:15 – 11:05 4 th 11:10 – 12:50 A(11:10)
Combining Like Terms. Only combine terms that are exactly the same!! Whats the same mean? –If numbers have a variable, then you can combine only ones.
FT-1105A FT-1205A 10/100Base-TX to 100Base-FX Redundant Media Converter Copyright © PLANET Technology Corporation. All rights reserved.
9-6 X-box Factoring ax 2 +bx+c. X-box Factoring This is a guaranteed method for factoring quadratic equations—no guessing necessary! We will learn how.
MULTIPLICATION EQUATIONS 1. SOLVE FOR X 3. WHAT EVER YOU DO TO ONE SIDE YOU HAVE TO DO TO THE OTHER 2. DIVIDE BY THE NUMBER IN FRONT OF THE VARIABLE.
MULT. INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
Diagnostic Interface For Optical Transceivers 20 min presentation for coming experts Bernt fiber course Robert Olsson/2009.
Photo Album by Robert MacKay.
Bottom’s Up 4 Possibilities. X Factor: 4 Options Smaller # - + Larger # Smaller # + Larger # -
Factoring Patterns There is a pattern for factoring trinomials of this form, when c is positive x² + bx + c.
SUBTRACTING INTEGERS 1. CHANGE THE SUBTRACTION SIGN TO ADDITION 2. TAKE THE INVERSE OF THE SECOND NUMBER 3. FOLLOW THE RULES FOR ADDITION 4. ADD THE OPPOSITE.
1 Copyright © 2013 Elsevier Inc. All rights reserved. Chapter 38.
Number your paper from Click on each to listen. Then write down your answer. Press enter to see the correct answers.
25 seconds left….. 24 seconds left….. 23 seconds left…..
DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.
2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt 2 pt 3 pt 4 pt 5 pt 1 pt Time Money AdditionSubtraction.
You have been given a mission and a code. Use the code to complete the mission and you will save the world from obliteration…
Test B, 100 Subtraction Facts
Cisco SFP-10G-LR Transceiver © 2015 FluxLight.
5.9 + = 10 a)3.6 b)4.1 c)5.3 Question 1: Good Answer!! Well Done!! = 10 Question 1:
FACTORING Think Distributive property backwards Work down, Show all steps ax + ay = a(x + y)
Combining Functions Sum, Difference, Product, and Quotient Functions.
© S Haughton more than 3?
1 © 1999, Cisco Systems, Inc. IP over DWDM NANOG May 24, 1999 Larry McAdams
Jeopardy Topic 1Topic Q 1Q 6Q 11Q 16Q 21 Q 2Q 7Q 12Q 17Q 22 Q 3Q 8Q 13Q 18Q 23 Q 4Q 9Q 14Q 19Q 24 Q 5Q 10Q 15Q 20Q 25 Final Jeopardy.
June 2007Mobile meeting Copenhagen0. Welcome to mobile meeting Copenhagen June 2007.
MULTIPLYING MONOMIALS TIMES POLYNOMIALS (DISTRIBUTIVE PROPERTY)
TWO STEP EQUATIONS 1. SOLVE FOR X 2. DO THE ADDITION STEP FIRST
Let’s take a 15 minute break Please be back on time.
1 © 2004, Cisco Systems, Inc. All rights reserved. CCNA 1 v3.1 Module 7 Ethernet Technologies.
We will resume in: 25 Minutes We will resume in: 24 Minutes.
ALGEBRAIC EXPRESSIONS Step 1 Write down the question Step 2 Plug in the numbers Step 3 Use PEMDAS Work down, Show all steps.
By D. Fisher Geometric Transformations. Reflection, Rotation, or Translation 1.
Empty Box Problems Subtraction = 3 If you start on 6 and jump back 3 spaces you land on
Module Ethernet Technology Module Ethernet Technology.
Mail-merge and Contact Log Shaun Elliott – Business Consultant Enhance your knowledge, improve your organisation.
Addition using three addends. An associative property is when you group numbers in anyway and the answer stays the same.
It is 2 o C The temperature drops by 3 degrees What temperature is it now? -1 o C.
FACTORING Think unfoil Work down, Show all steps ax 2 + bx + c.
Past Tense Probe Past Tense Probe – Practice 1 Past Tense Probe – Practice 2.
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