Presentation is loading. Please wait.

Presentation is loading. Please wait.

IV.13. HYDROLYSIS (Hebden p. 144 – 148). Hydrolysis of a Salt Rx between water and cation &/or anion in salt that produces an acidic or basic solution.

Similar presentations


Presentation on theme: "IV.13. HYDROLYSIS (Hebden p. 144 – 148). Hydrolysis of a Salt Rx between water and cation &/or anion in salt that produces an acidic or basic solution."— Presentation transcript:

1 IV.13. HYDROLYSIS (Hebden p. 144 – 148)

2 Hydrolysis of a Salt Rx between water and cation &/or anion in salt that produces an acidic or basic solution All salts are 100% ionized in water

3 Spectator Ions Do NOT react with water The conjugates of STRONG acids and bases

4 Spectator Cations Alkali metals Alkaline earth metals Ex: NaOH Na + + OH -

5 Spectator Anions 1st top of Acid/ Base Table (not HSO 4 - b/c it is a weak acid) Ex: HCl H + + Cl -

6 To determine the behavior of salt in water… Determine ions Discard spectators Remaining ions are acids if on acid side of table or bases if on base side of table

7 Ex #1: NaCl Na + + Cl - Both Na + and Cl - are spectators Therefore, solution is NEUTRAL

8 2. NH 4 Cl NH Cl - Cl - is a spectator Solution is acidic NH H 2 O = H 3 O + + NH 3

9 3. NaF Na + + F - Na + is a spectator Solution is basic F - + H 2 0 = HF + OH -

10 4. NaHC 2 O 4 Na + +HC 2 O 4 - Na + is a spectator Solution either acidic or basic b/c HC 2 O 4 - is amphiprotic We must determine which rx is predominant

11 Ka for HC 2 O 4 - = 6.4 x Kb = Kw /Ka = 1.00 x / 5.9 x = 1.7 x Ka > Kb so solution is acidic HC 2 O H 2 0 = H 3 O + +C 2 O 4 2-

12 5. NH 4 NO 2 NH NO 2 - No spectators Must determine predominant rx

13 Ka of NH 4 + = 5.6 x Kb of NO 2 - = Kw/Ka = 1.0 x / 4.6 x = 2.2 x Solution is acidic NH H 2 0 = H 3 O + + NH 3


Download ppt "IV.13. HYDROLYSIS (Hebden p. 144 – 148). Hydrolysis of a Salt Rx between water and cation &/or anion in salt that produces an acidic or basic solution."

Similar presentations


Ads by Google