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1 Chapter 14 Acids and Bases 14.6 The pH Scale Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

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2 pH Scale The pH scale: Is used to indicate the acidity of a solution. Has values that usually range from 0 to 14. Is acidic when the values are less than 7. Is neutral with a pH of 7. Is basic when the values are greater than 7.

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3 pH of Everyday Substances Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

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4 Identify each solution as 1. acidic 2. basic3. neutral A. ___ HCl with a pH = 1.5 B. ___ Pancreatic fluid [H 3 O + ] = 1 x 10 −8 M C. ___ Sprite soft drink pH = 3.0 D. ___ pH = 7.0 E. ___ [OH − ] = 3 x 10 −10 M F. ___ [H 3 O + ] = 5 x 10 −12 Learning Check

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5 A. 1 HCl with a pH = 1.5 B. 2 Pancreatic fluid [H 3 O + ] = 1 x 10 −8 M C. 1 Sprite soft drink pH = 3.0 D. 3 pH = 7.0 E. 1 [OH - ] = 3 x 10 −10 M F. 2 [H 3 O + ] = 5 x 10 −12 Solution

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6 Testing the pH of Solutions The pH of solutions can be determined using pH meter, pH paper, or indicators that have specific colors at different pH values. Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

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7 pH Range Table 14.8 Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

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8 pH is the negative log of the hydronium ion concentration. pH = - log [H 3 O + ] For a solution with [H 3 O + ] = 1 x 10 −4 pH =−log [1 x 10 −4 ] pH = - [-4.0] pH = 4.0 Calculating pH

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9 Significant Figures in pH When expressing log values, the number of decimal places in the pH is equal to the number of significant figures in the coefficient of [H 3 O + ]. [H 3 O + ] = 1 x pH = 4.0 [H 3 O + ] = 8.0 x pH = 5.10 [H 3 O + ] = 2.4 x pH = 7.62

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10 Guide to pH Calculations Copyright © 2008 by Pearson Education, Inc. Publishing as Benjamin Cummings

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11 Find the pH of a solution with a [H 3 O + ] of 1.0 x 10 −3 : STEP 1 Enter [H 3 O + ] Enter 1 x by pressing 1 (EE) 3 The EE key gives an exponent of 10 and change sign (+/- key or – key) STEP 2 Press log key and change sign - log (1 x 10 −3 ) = -[-3] STEP 3 Adjust significant figures after decimal point Two significant figures in 1.0 x 10 −3 Calculating pH

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12 A. The [H 3 O + ] of tomato juice is 2 x 10 −4 M. What is the pH of the solution? 1) 4.02) 3.73) 10.3 B. The [OH − ] of a solution is 1.0 x 10 −3 M. What is the pH of the solution? 1) 3.002) ) Learning Check

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13 A. 2) 3.7 pH = - log [ 2 x ] = (EE) 4 (+/-) log (+/-) B. 2) Use the K w to obtain [H 3 O + ] = 1.0 x 10 −11 pH = - log [1.0 x 10 −11 ] 1.0 (EE) 11 (+/-) log (+/-) Solution

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14 pOH The pOH of a solution Is analogous to the pH value on the pH scale. Is based on the [OH − ]. Has high pOH values with low [OH − ] and high [H 3 O + ]. Is equal to the - log [OH - ] pOH = - log [OH - ]. Added to the pH value is equal to pH + pOH = 14.0

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15 Calculation pOH Find the pOH of a solution with a [OH − ] of 2.0 x 10 −3. STEP 1 Enter [OH − ] STEP 2 Press log key and change sign - log (2.0 x 10 −3 ) = -[ ] = STEP 3 Adjust figures after decimal point 2.70 Two significant figures in 2.0 x 10 −3

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16 Calculating [H 3 O + ] from pH The [H 3 O + ] can be expressed by using the pH as the negative power of 10. [H 3 O + ] = 1 x 10 −pH If the pH is 3.0, the [H 3 O + ] = 1 x 10 −3 On a calculator 1. Enter the pH value Change sign Use the inverse log key (or 10 x ) to obtain the [H ]. =1 x 10 −3 M

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17 A. What is the [H 3 O + ] of a solution with a pH of 10.0? 1) 1 x 10 −4 M2) 1 x M 3) 1 x 10 −10 M B. What is the [H 3 O + ] of a solution with a pH of 5.75? 1) 1.8 x 10 − 6 M2) x 10 −6 M 3) 2 x 10 −6 M Learning Check

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18 A. What is the [H 3 O + ] of a solution with a pH of 10.0? 3) 1 x M1 x 10 -pH B. What is the [H 3 O + ] of a solution with a pH of 5.75? 1) 1.8 x 10 − 6 M 5.75 (+/-) inv log (or 10 x ) = 1.8 x Note: Two decimal places (.75), indicate two significant figures in the coefficient of the answer. Solution

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19 Learning Check What is the pH and the pOH of coffee if the [H 3 O + ] is 1 x 10 −5 M? 1) pH = 5.0 pOH =7.0 2) pH = 7.0 pOH = 9.0 3) pH = 5.0pOH = 9.0

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20 Solution What is the pH and the pOH of coffee if the [H 3 O + ] is 1 x 10 −5 M? 3) pH = 5.0pOH = 9.0 pH = -log [1 x 10 −5 ] = -(-5.0) = 5.0 pH + pOH = 14.0 pOH = 14.0 – pH = 14.0 – 5.0 = 9.0 or [OH - ] = 1 x 10 −9 pOH = - log [1 x 10 −9 ] = -(-9.0) = 9.0

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