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Warm up #9 ch 6: Solve for x 1 (x – 3)(x + 5) = 0 2 (2x – 4)x = 0 3 x 2 + 4x + 3 = 0 4 X 2 + 6x + 9 = 0 5 9x 2 – 16 = 0 x = 3 or -5 x = 0 or 2 x = -1 or -3 x = -3

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6.9 Using Equations that Factor Goal: Solve problems by writing and solving equation

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Translate to an equation and solve. 1. The product of two consecutive positive even integers is 48. Find the two integers. Let n = first even integer (n + 2) = 2nd even integer n(n + 2) = 48 n 2 + 2n = 48 n 2 + 2n - 48= 0 (n + 8)(n – 6)= 0 n = -8, 6 X 6 and 8

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Translate to an equation and solve. 1. The product of two consecutive positive odd integers is 143. Find the two integers. Let n = first odd integer (n + 2) = 2nd odd integer n(n + 2) = 143 n 2 + 2n = 143 n 2 + 2n - 143= 0 (n - 11)(n + 13)= 0 n = -13, 11 X 11 and 13

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2. One side of a rectangle is 4 in. longer than the other. If the sides are each increased by 2 in., the area of the new rectangle is 60 in 2. How long are the sides of the original rectangle? (x+2)(x +6) = 60 x 2 + 8x + 12 = 60 x 2 + 8x - 48= 0 (x + 12)(x – 4)= 0 x = -12, 4 X 4 and 8 X X+4 X+2 X+4+2 A = 60 in 2

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The sum of the squares of two consecutive even integers is 244. Find the two integers. 10 and 12. Also, -12 and -10 Let n² = first consecutive square Let (n+2)² = the 2 nd consecutive square (n)² +(n+2) ²=244 n² +n² +4n +4 =244 2n² +4n +4 =244 2(n²+2n +2) =244 n² +2n +2 =122 n²+2n -120 =0 (n-10) (n+12) =0 n-10 =0 or n +12 =0 If n=10 then n+2 = 12 If n =-12 then n+2 =-10

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Page 294, 1 - 20

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7,8 and –7, -8

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Assignment: Page 294 (2-20) even

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Page 294, 1 - 20 13,14 and –13, -14

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Page 294, 1 - 20

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DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.

DIVIDING INTEGERS 1. IF THE SIGNS ARE THE SAME THE ANSWER IS POSITIVE 2. IF THE SIGNS ARE DIFFERENT THE ANSWER IS NEGATIVE.

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