Presentation on theme: "Momentum, Impulse, and Collisions. Momentum (P) A quantity that expresses the motion of a body and its resistance to slowing down. P = mv m = mass (kg)"— Presentation transcript:
Another one… An 8N force acts upon an object for 5 seconds. What impulse is given this object? 40N·s
Putting it all together… F=ma (Newton’s 2 nd Law) a=Δv/t Insert “Δv/t” for “a” in “F=ma” This gives us “F=mΔv/t” Multiply by “t” to get- F(t) = m(v f -v i ) Notice impulse, on the left side, is equal to the change in momentum of an object.
Try it… A ball changes velocity from 20m/s to 30m/s. If it has a mass of 5kg, what impulse was necessary to cause this change? 50N·s How long would it take a 5N force to change the velocity of the ball? (Hint: use Impulse=F(t)) 10s
The Law of Conservation of Momentum In an isolated system, the total momentum does not change. The total momentum remains constant in any type of collision.
Two Types of Collisions…. Elastic The two objects collide and then separate. Inelastic When two objects collide and move together as one mass.
There are 2 types of collisions Elastic m 1i v 1i + m 2i v 2i = m 1f v 1f + m 2f v 2f Where 1 implies object 1, 2 implies object 2 Where i implies initial & f implies final Inelastic m 1i v 1i + m 2i v 2i = m T v T Where T implies total Use + and – velocities to show direction.
Try these… A 2kg ball strikes another ball head on at an initial velocity of +2m/s. If the second ball had a mass of 3kg and was initially moving at -1m/s, what is the final velocity of the 2kg ball if the v f of the 3kg ball is now +1.33m/s? Set it up- m 1i v 1i + m 2i v 2i = m 1f v 1f + m 2f v 2f 2kg(2m/s)+3kg(-1m/s) = 2kg(v 1f )+3kg(1.33m/s) v 1f = -1.5m/s
Last one… A 500kg car is driving at a velocity of 10m/s. Another car (700kg) hits it from behind at a velocity of 25m/s and the two cars interlock bumpers. What is the resulting velocity of the two cars? Set it up- m 1i v 1i + m 2i v 2i = m T v T 500kg(10m/s)+700kg(25m/s) = 1,200kg(v T ) v T = 18.75 m/s
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