# “Teach A Level Maths” Vol. 2: A2 Core Modules

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“Teach A Level Maths” Vol. 2: A2 Core Modules
33: The equation © Christine Crisp

Module C3 Module C4 Edexcel AQA OCR MEI/OCR
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Can you see why one of these equations is easy to solve and the other takes much more work ?
(b) Both have 2 trig ratios but (a) can be solved by dividing by We get This is a simple equation and can now be solved.

Can you see why one of these equations is easy to solve and the other takes much more work ?
(b) If we try the same method with (b), we get This is no better than the original equation as we still have 2 trig ratios.

However, we saw in the previous section that
so the equation can be written as Dividing by 5: This is of the form where so we can find solutions for and then find x by adding to each one.

e.g. 1 Solve the following equation giving the solutions in the interval correct to 1 d.p.
Let Coef. of : Coef. of :

Substituting into the l.h.s. of the equation:
Beware ! Don’t find x at this stage. We have NOT The 2nd solution will be wrong if we use the x value to try to find it. At this stage we need to get all the solutions for . So, ( Subtract from each part )

We sketch the usual cosine graph:
Outside the required interval

We sketch the usual cosine graph:
Add : ANS: x is ( 1 d.p. )

SUMMARY To solve the equation Write the l.h.s. in one of the forms Calculate the interval for using the one given for x, where or Solve the equation to find making sure you find all the solutions. Find the values of x. N.B. for , add a and for , subtract a.

Exercise 1(a) Write in the form where R and a are exact. (b) Solve the equation for 2. Solve the equation for ( Notice the different letter in the equation. You need to be able to cope with a switch of letters. )

Solutions: 1(a) Coef. of : Coef. of : So,

Solutions: for 1(b) Solve so, the equation becomes

Solutions: 2. Solve Let Coef. of : Coef. of : So, So, becomes

Solutions: for Solve

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(a) (b) Both have 2 trig ratios but (a) can be solved by dividing by We get This is a simple equation and can now be solved. Think about these 2 equations.

If we try the same method with (b), we get
This is no better than the original equation as we still have 2 trig ratios. so the equation can be written as Dividing by 5: However, we saw in the previous section that This is now a simple equation which can be solved.

e.g. 1 Solve the following equation giving the solutions in the interval correct to 1 d.p.
Let Coef. of :

Substituting into the l.h.s. of the equation:
At this stage we need to get all the solutions for . So, Beware ! Don’t find x at this stage. We have NOT The 2nd solution will be wrong if we use the x value to try to find it. ( Subtract from each part )

We sketch the usual cosine graph:
Add : ANS: x is ( 1 d.p. )

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