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Solving Equations II. Solving an Equation by Balancing Zaid places the same number of counters in 3 paper bags and has 2 left over. Then he asks Steven.

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Presentation on theme: "Solving Equations II. Solving an Equation by Balancing Zaid places the same number of counters in 3 paper bags and has 2 left over. Then he asks Steven."— Presentation transcript:

1 Solving Equations II

2 Solving an Equation by Balancing Zaid places the same number of counters in 3 paper bags and has 2 left over. Then he asks Steven how many counters are in each bag. Stevens only clue is that the total number of counters on the left is the same as the total number of counters on the right which is 17. How can you determine the number of counters in each bag?

3 What do we know? The total number of counters is 17. There are 3 bags with an unknown (variable) equal amount inside of them. There are 2 counters left over. What will the formula look like?

4 Formula 3n+2=17 How do we solve for n?

5 Solving for n 3n+2=17 3n+2-2=17-2 3n=15 3n/3=15/3 n= 5 Therefore there are 5 counters in each bag.

6 Question 2 3 full bags of sand all have the same mass. When 4.5g of sand is removed from the third bag, the total mass of the three bags is 233.7g. What is the mass of each full bag of sand.

7 What do we know? The current total mass is 233.7g. There are 3 bags with an unknown (variable) equal amount in them. 4.5g was taken out of one bag. What will the formula look like?

8 Formula 3b-4.5=233.7 How do we solve for b?

9 Solving for b 3b-4.5= b = b= b/3=238.2/3 b= 79.4 grams Therefore each bag when equal has 79.4 grams of sand in it.

10 Homework Pg. 270 Questions: 6-9, 11,12, 14, 15


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