# Heating up a substance - Specific heat Q = mc  T Q - Heat (in J) m - Mass (in kg) c - Specific Heat (in J o C -1 kg -1 )  T - Change in temp. ( o C)

## Presentation on theme: "Heating up a substance - Specific heat Q = mc  T Q - Heat (in J) m - Mass (in kg) c - Specific Heat (in J o C -1 kg -1 )  T - Change in temp. ( o C)"— Presentation transcript:

Heating up a substance - Specific heat Q = mc  T Q - Heat (in J) m - Mass (in kg) c - Specific Heat (in J o C -1 kg -1 )  T - Change in temp. ( o C) Q -> Kinetic Energy of molecules (Temperature rises) Some specific heats (in J o C -1 kg -1 ) H 2 O liquid 4186 H 2 O ice2100 H 2 O steam2010 Aluminum900 Iron450 More in your book.

Heating up a substance - Specific heat Some specific heats (in J o C -1 kg -1 )(in J o C -1 mol -1 ) Aluminum90024.4 Carbon5076.11 Copper38624.5 Lead12826.5 Silver23625.5 Tungsten13424.8

Q = mc  T Q = ??, m = 1.5 kg, c = 4186 J o C -1 kg -1,  T = 5.0 o C 31,000 J Example: A. Nicholas Cheep wants to calculate what heat is needed to raise 1.5 liters (1 liter = 1 kg) of water by 5.0 o C. Can you help him? (c = 4186 J o C -1 kg -1 )

Q = mc  T Q = 817 J, m = 0.512 kg, c = 450. J o C -1 kg -1,  T = ?? 3.55 o C Adella Kutessen notices what change in temperature if 512 g of iron absorbs 817 J of heat (c = 450. J o C -1 kg -1 )

Q = mc  T Q = 12,000 J, m = ??, c = 900. J o C -1 kg -1,  T = 3.45 o C 3.9 kg Anita Break notices that a chunk of Aluminium absorbs 12,000 J of heat while raising its temperature a mere 3.45 o C Of what mass is this chunk? (c = 900. J o C -1 kg -1 )

Q = mc  T Q = 12,510 J, m = 5.412 kg, c = ??,  T = 2.19 o C 1060 J o C -1 kg -1 Anne Sodafone does an experiment where 5.412 kg of a mystery substance absorbs 12,510 J of heat while raising its temperature 2.19 o C What is the specific heat?

Download ppt "Heating up a substance - Specific heat Q = mc  T Q - Heat (in J) m - Mass (in kg) c - Specific Heat (in J o C -1 kg -1 )  T - Change in temp. ( o C)"

Similar presentations