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Review Chapter 7 Algebra II JEOPARDY Jeopardy Review.

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Presentation on theme: "Review Chapter 7 Algebra II JEOPARDY Jeopardy Review."— Presentation transcript:

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2 Review Chapter 7 Algebra II JEOPARDY Jeopardy Review

3 Logarithms Exponential Growth and Decay Exponential FunctionsSolvingLogarithmicEquationsSolvingExponentialEquations

4 Logarithms 200 log 3 (1/9) = A: -2 Jeopardy Review

5 Logarithms 400 A: -3 log.001 Jeopardy Review

6 Logarithms 600 A: Use the change of base formula to evaluate: log 6 21 Jeopardy Review

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8 Logarithms 800 A: 2 log x + log y – log z Jeopardy Review Using the properties of logarithms, expand log (x 2 y/z)

9 Logarithms 1000 A: log (m 4 n 2 /k 3) Write as a single logarithm: y = 4 log m + 2 log n – 3 log k S2C13 Jeopardy Review

10 Exponential Growth & Decay 200 A: 52% Identify the percent of decay in the equation: y = 6000 (.48) x S2C13 Jeopardy Review

11 Exponential Growth & Decay 400 A: y = 22,000 (1.06) x Write the equation that models exponential growth of 6% per year with a starting population of 22,000. S2C13 Jeopardy Review

12 Exponential Growth & Decay 600 A: 2.62 million Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04) x where x represents the years after S2C13 Jeopardy Review

13 Exponential Growth & Decay 800 A: 2022 A citys population is modeled by the equation y = 14,000 (.98) x, where x represents the number of years after the year Predict during which year the population will decrease to 8,900. S2C13 Jeopardy Review

14 Exponential Growth & Decay 1000 A: a) growth b) 2.58 c) 158% In the equation: y = 13 (2.58) x, Identify a)Growth or decay b)Growth or decay factor c)Percent of growth or decay S2C13 Jeopardy Review

15 Exponential Functions 200 A: y = ½, 1, and 4 Evaluate y = 2 x for x = -1, 0, and 2. S2C13 Jeopardy Review

16 Exponential Functions 400 A: y = (7/16)(2) x Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). S2C13 Jeopardy Review

17 Exponential Functions 600 A: 20,000 e^(.06*5) = $26, Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously. S2C13 Jeopardy Review

18 Exponential Functions 800 A: 3000 e (.05)(3) = $ Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously. S2C13 Jeopardy Review

19 Exponential Functions 1000 A: 2500 = 2000 e (.03t) t = 7.44 years You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500? S2C13 Jeopardy Review

20 Solving Logarithmic Equations 200 A: log 2 8 = 3 2 log 2 4 – log 2 2 = S2C13 Jeopardy Review

21 Solving Logarithmic Equations 400 A: 1 log 9 81 S2C13 Jeopardy Review

22 Solving Logarithmic Equations 600 A: 10 2 = 5x x = 20 Solve for x. log 5x = 2 S2C13 Jeopardy Review

23 Solving Logarithmic Equations 800 A: ln (3x/2) = 6 x = Solve for x. ln 3 + ln x – ln 2 = 6 S2C13 Jeopardy Review

24 Solving Logarithmic Equations 1000 A: ln (x 2 + 3x) = 2 x = 1.6, using quadratic formula ln x + ln (x + 3) = 2 S2C13 Jeopardy Review

25 Solving Exponential Equations 200 A: 7 or -7 x 2 = 49 S2C13 Jeopardy Review

26 Solving Exponential Equations 400 A: x = x = 20 S2C13 Jeopardy Review

27 Solving Exponential Equations 600 A: x = x – 4 = 6 S2C13 Jeopardy Review

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29 Solving Exponential Equations 800 A: m = 16 4 m = 10 S2C13 Jeopardy Review

30 e 4x = 10 Solving Exponential Equations 1000 A: 4x = ln 10x =.576 S2C13 Jeopardy Review


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