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Chapter 7 Algebra II Review JEOPARDY Jeopardy Review

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Logarithms Exponential Growth and Decay Exponential Functions Solving Logarithmic Equations Solving Exponential Equations 200 200 200 200 200 400 400 400 400 400 600 600 600 600 600 800 800 800 800 800 1000 1000 1000 1000 1000

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Logarithms 200 log3 (1/9) = A: -2 Jeopardy Review

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Logarithms 400 log .001 A: -3 Jeopardy Review

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**Use the change of base formula to evaluate: log6 21**

Logarithms 600 Use the change of base formula to evaluate: log6 21 A: Jeopardy Review

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Daily Double Jeopardy Review

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**Using the properties of logarithms, expand log (x2y/z)**

A: 2 log x + log y – log z Jeopardy Review

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**Write as a single logarithm:**

Logarithms 1000 Write as a single logarithm: y = 4 log m + 2 log n – 3 log k A: log (m4n2/k3) S2C13 Jeopardy Review

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**Exponential Growth & Decay 200**

Identify the percent of decay in the equation: y = 6000 (.48)x A: 52% S2C13 Jeopardy Review

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**Exponential Growth & Decay 400**

Write the equation that models exponential growth of 6% per year with a starting population of 22,000. A: y = 22,000 (1.06)x S2C13 Jeopardy Review

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**Exponential Growth & Decay 600**

Predict the population in the year 2006 if a countries population (in millions) is growing by 4% each year, and is modeled by the equation y = 1.4 (1.04)x where x represents the years after 1990. A: million S2C13 Jeopardy Review

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**Exponential Growth & Decay 800**

A city’s population is modeled by the equation y = 14,000 (.98)x, where x represents the number of years after the year Predict during which year the population will decrease to 8,900. A: 2022 S2C13 Jeopardy Review

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**Exponential Growth & Decay 1000**

In the equation: y = 13 (2.58)x, Identify Growth or decay Growth or decay factor Percent of growth or decay A: a) growth b) c) 158% S2C13 Jeopardy Review

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**Exponential Functions 200**

Evaluate y = 2x for x = -1, 0, and 2. A: y = ½, 1, and 4 S2C13 Jeopardy Review

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**Exponential Functions 400**

Write the equation to describe the exponential function with a base of 2, passing through the point (4,7). A: y = (7/16)(2)x S2C13 Jeopardy Review

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**Exponential Functions 600**

Find the amount of money you have if you invest $20,000 for 5 years at 6% compounded continuously. A: 20,000 e^(.06*5) = $26,977.18 S2C13 Jeopardy Review

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**Exponential Functions 800**

Find the amount of money you have if you invest $3000 for 3 years at 5% compounded continuously. A: 3000 e (.05)(3) = $ S2C13 Jeopardy Review

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**Exponential Functions 1000**

You invest $2000 in an account earning 3% interest compounded continuously. How long will it be until you have $2500? A: = 2000 e (.03t) t = 7.44 years S2C13 Jeopardy Review

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**Solving Logarithmic Equations 200**

2 log24 – log22 = A: log28 = 3 S2C13 Jeopardy Review

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**Solving Logarithmic Equations 400**

S2C13 Jeopardy Review

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**Solving Logarithmic Equations 600**

Solve for x. log 5x = 2 A: 102 = 5x x = 20 S2C13 Jeopardy Review

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**Solving Logarithmic Equations 800**

Solve for x. ln 3 + ln x – ln 2 = 6 A: ln (3x/2) = x = S2C13 Jeopardy Review

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**Solving Logarithmic Equations 1000**

ln x + ln (x + 3) = 2 A: ln (x2 + 3x) = x = 1.6, using quadratic formula S2C13 Jeopardy Review

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**Solving Exponential Equations 200**

A: 7 or -7 S2C13 Jeopardy Review

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**Solving Exponential Equations 400**

A: x = S2C13 Jeopardy Review

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**Solving Exponential Equations 600**

A: x = 2.096 S2C13 Jeopardy Review

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Daily Double

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**Solving Exponential Equations 800**

4√m = 10 A: m = 16 S2C13 Jeopardy Review

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**Solving Exponential Equations 1000**

A: 4x = ln 10 x = .576 S2C13 Jeopardy Review

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Solving Equations Exponential Logarithmic Applications.

Solving Equations Exponential Logarithmic Applications.

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