Presentation on theme: "Resonance in a Closed Tube"— Presentation transcript:
1Resonance in a Closed Tube Constant Length, Changing Frequency
2Review: Changing Length First resonance point:≈ Half of difference ( ½ Δx).Decreases as f increases.Antinode to node.xinitial ≈ ¼ λ … End correction!Distance between resonance points:Constant for same frequency.Decreases as f increases.Node to node.Δx = ½ λ
5What about constant length? When resonating, net displacement of molecules is zero.Amplitude at resonance points is a relative maximum, because the sound is loudest.Constant length:Constant velocity, b/c constant T.Changing frequency & wavelength, b/c length changes.
8Frequency, Wavelength, and Speed of ANY wave, including Sound: v = f λKnow two, find the third!Wavelength calculated as a fraction of L, or L calculated from λ.Speed calculated: v = T.Frequency: measured or calculated.
9Open TubeUsing the analysis of a closed tube as a guide, determine the frequencies at which an open tube of fixed length will resonate.