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Holt McDougal Geometry Measuring and Constructing Segments How do I use length and midpoint of a segment? Essential Questions.

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Presentation on theme: "Holt McDougal Geometry Measuring and Constructing Segments How do I use length and midpoint of a segment? Essential Questions."— Presentation transcript:

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2 Holt McDougal Geometry Measuring and Constructing Segments How do I use length and midpoint of a segment? Essential Questions

3 Holt McDougal Geometry Measuring and Constructing Segments coordinatemidpoint distancebisect lengthsegment bisector construction between congruent segments Vocabulary

4 Holt McDougal Geometry Measuring and Constructing Segments AB = |a – b| or |b - a| A a B b The distance between any two points is the absolute value of the difference of the coordinates. If the coordinates of points A and B are a and b, then the distance between A and B is |a – b| or |b – a|. The distance between A and B is also called the length of AB, or AB.

5 Holt McDougal Geometry Measuring and Constructing Segments Congruent segments are segments that have the same length. In the diagram, PQ = RS, so you can write PQ  RS. This is read as “segment PQ is congruent to segment RS.” Tick marks are used in a figure to show congruent segments.

6 Holt McDougal Geometry Measuring and Constructing Segments In order for you to say that a point B is between two points A and C, all three points must lie on the same line, and AB + BC = AC.

7 Holt McDougal Geometry Measuring and Constructing Segments Example 1: Using the Segment Addition Postulate M is between N and O. Find NO. 10 = 2x NM + MO = NO Seg. Add. Postulate 17 + (3x – 5) = 5x + 2 – 2 – 2 Substitute the given values Subtract 2 from both sides. Simplify. 3x + 12 = 5x + 2 3x + 10 = 5x –3x –3x = x Simplify. Subtract 3x from both sides. Divide both sides by 2.

8 Holt McDougal Geometry Measuring and Constructing Segments Example 1 Continued M is between N and O. Find NO. NO = 5x + 2 Substitute 5 for x. Simplify. = 27 = 5(5) + 2

9 Holt McDougal Geometry Measuring and Constructing Segments E is between D and F. Find DF. Check It Out! Example 2 DE + EF = DF Seg. Add. Postulate (3x – 1) + 13 = 6x – 3x Substitute the given values Subtract 3x from both sides. 3x + 12 = 6x 12 = 3x 4 = x Simplify. Divide both sides by x 3 3 =

10 Holt McDougal Geometry Measuring and Constructing Segments E is between D and F. Find DF. Check It Out! Example 2 Continued DF = 6x Substitute 4 for x. Simplify. = 24 = 6(4)

11 Holt McDougal Geometry Measuring and Constructing Segments The midpoint M of AB is the point that bisects, or divides, the segment into two congruent segments. If M is the midpoint of AB, then AM = MB. So if AB = 6, then AM = 3 and MB = 3.

12 Holt McDougal Geometry Measuring and Constructing Segments Example 3: Recreation Application The map shows the route for a race. You are at X, 6000 ft from the first checkpoint C. The second checkpoint D is located at the midpoint between C and the end of the race Y. The total race is 3 miles. How far apart are the 2 checkpoints? XY = 3(5280 ft) Convert race distance to feet. = 15,840 ft

13 Holt McDougal Geometry Measuring and Constructing Segments Example 3 Continued XC + CY = XY Seg. Add. Post CY = 15,840 Substitute 6000 for XC and 15,840 for XY. – 6000 Subtract 6000 from both sides. Simplify. CY = 9840 = 4920 ft The checkpoints are 4920 ft apart. D is the mdpt. of CY, so CD = CY.

14 Holt McDougal Geometry Measuring and Constructing Segments Example 4: Using Midpoints to Find Lengths D F E 4x + 6 7x – 9 4x + 6 = 7x – 9 6 = 3x – 9 15 = 3x Step 1 Solve for x. ED = DF –4x Substitute 4x + 6 for ED and 7x – 9 for DF. D is the mdpt. of EF. Subtract 4x from both sides. Simplify. Add 9 to both sides. Simplify. D is the midpoint of EF, ED = 4x + 6, and DF = 7x – 9. Find ED, DF, and EF.

15 Holt McDougal Geometry Measuring and Constructing Segments Example 4 Continued D F E 4x + 6 7x – 9 ED = 4x + 6 = 4(5) + 6 = 26 DF = 7x – 9 = 7(5) – 9 = 26 EF = ED + DF = = 52 Step 2 Find ED, DF, and EF. D is the midpoint of EF, ED = 4x + 6, and DF = 7x – 9. Find ED, DF, and EF.

16 Holt McDougal Geometry Measuring and Constructing Segments Check It Out! Example 5 S is the midpoint of RT, RS = –2x, and ST = –3x – 2. Find RS, ST, and RT. ST R –2x–3x – 2 –2x = –3x – 2 x = –2 Step 1 Solve for x. RS = ST +3x Substitute –2x for RS and –3x – 2 for ST. S is the mdpt. of RT. Add 3x to both sides. Simplify.

17 Holt McDougal Geometry Measuring and Constructing Segments Check It Out! Example 5 Continued S is the midpoint of RT, RS = –2x, and ST = –3x – 2. Find RS, ST, and RT. ST R –2x–3x – 2 RS = –2x = –2(–2) = 4 ST = –3x – 2 = –3(–2) – 2 = 4 RT = RS + ST = = 8 Step 2 Find RS, ST, and RT.

18 Holt McDougal Geometry Measuring and Constructing Angles The set of all points between the sides of the angle is the interior of an angle. The exterior of an angle is the set of all points outside the angle. Angle Name R, SRT, TRS, or 1 You cannot name an angle just by its vertex if the point is the vertex of more than one angle. In this case, you must use all three points to name the angle, and the middle point is always the vertex.

19 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 6 Write the different ways you can name the angles in the diagram. RTQ, T, STR, 1, 2

20 Holt McDougal Geometry Measuring and Constructing Angles The measure of an angle is usually given in degrees. Since there are 360° in a circle, one degree is of a circle. When you use a protractor to measure angles, you are applying the following postulate.

21 Holt McDougal Geometry Measuring and Constructing Angles You can use the Protractor Postulate to help you classify angles by their measure. The measure of an angle is the absolute value of the difference of the real numbers that the rays correspond with on a protractor. If OC corresponds with c and OD corresponds with d, mDOC = |d – c| or |c – d|.

22 Holt McDougal Geometry Measuring and Constructing Angles

23 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 7 Use the diagram to find the measure of each angle. Then classify each as acute, right, or obtuse. a. BOA b. DOB c. EOC mBOA = 40° mDOB = 125° mEOC = 105° BOA is acute. DOB is obtuse. EOC is obtuse.

24 Holt McDougal Geometry Measuring and Constructing Angles Congruent angles are angles that have the same measure. In the diagram, mABC = mDEF, so you can write ABC  DEF. This is read as “angle ABC is congruent to angle DEF.” Arc marks are used to show that the two angles are congruent. The Angle Addition Postulate is very similar to the Segment Addition Postulate that you learned in the previous lesson.

25 Holt McDougal Geometry Measuring and Constructing Angles

26 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 8 mXWZ = 121° and mXWY = 59°. Find mYWZ. mYWZ = mXWZ – mXWY mYWZ = 121 – 59 mYWZ = 62  Add. Post. Substitute the given values. Subtract.

27 Holt McDougal Geometry Measuring and Constructing Angles An angle bisector is a ray that divides an angle into two congruent angles. JK bisects LJM; thus LJK  KJM.

28 Holt McDougal Geometry Measuring and Constructing Angles Example 9: Finding the Measure of an Angle KM bisects JKL, mJKM = (4x + 6)°, and mMKL = (7x – 12)°. Find mJKM.

29 Holt McDougal Geometry Measuring and Constructing Angles Example 9 Continued Step 1 Find x. mJKM = mMKL (4x + 6)° = (7x – 12)° +12 4x + 18 = 7x –4x 18 = 3x 6 = x Def. of  bisector Substitute the given values. Add 12 to both sides. Simplify. Subtract 4x from both sides. Divide both sides by 3. Simplify.

30 Holt McDougal Geometry Measuring and Constructing Angles Example 9 Continued Step 2 Find mJKM. mJKM = 4x + 6 = 4(6) + 6 = 30 Substitute 6 for x. Simplify.

31 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 10 Find the measure of each angle. QS bisects PQR, mPQS = (5y – 1)°, and mPQR = (8y + 12)°. Find mPQS. 5y – 1 = 4y + 6 y – 1 = 6 y = 7 Def. of  bisector Substitute the given values. Simplify. Subtract 4y from both sides. Add 1 to both sides. Step 1 Find y.

32 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 10 Continued Step 2 Find mPQS. mPQS = 5y – 1 = 5(7) – 1 = 34 Substitute 7 for y. Simplify.

33 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 11 Find the measure of each angle. JK bisects LJM, mLJK = (-10x + 3)°, and mKJM = (–x + 21)°. Find mLJM. LJK = KJM (–10x + 3)° = (–x + 21)° –9x + 3 = 21 x = –2 Step 1 Find x. –9x = 18 +x +x –3 Def. of  bisector Substitute the given values. Add x to both sides. Simplify. Subtract 3 from both sides. Divide both sides by –9. Simplify.

34 Holt McDougal Geometry Measuring and Constructing Angles Check It Out! Example 11 Continued Step 2 Find mLJM. mLJM = mLJK + mKJM = (–10x + 3)° + (–x + 21)° = –10(–2) + 3 – (–2) + 21Substitute –2 for x. Simplify.= = 46°

35 Holt McDougal Geometry Measuring and Constructing Angles Assignment Segments page #12, 16-23, 28-29, 31-32, Angles page #16-18, 27, 29-38, 41-44


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