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Unit 5, Lesson 1. Do Now Solve: 1.|x + 2| = 5 x + 2 = 5 or x + 2 = -5  x = 3 or -7 2.|x + 4| < 8 x + 4 -8  x -12.

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Presentation on theme: "Unit 5, Lesson 1. Do Now Solve: 1.|x + 2| = 5 x + 2 = 5 or x + 2 = -5  x = 3 or -7 2.|x + 4| < 8 x + 4 -8  x -12."— Presentation transcript:

1 Unit 5, Lesson 1

2 Do Now Solve: 1.|x + 2| = 5 x + 2 = 5 or x + 2 = -5  x = 3 or -7 2.|x + 4| < 8 x  x -12

3 Be able to graph inequalities and absolute value inequalities Be able to use the Distance Formula Be able to use the Midpoint Formula Vocabulary: quadrants, origin, ordered pair, Pythagorean Theorem HW: Read p Do p. 142: 11, 13, 15, 17, 21, 27, 31, 33, 35, 41 HW & Objectives

4 Review 1. Plotting Points of Coordinate Plane a)x & y axes; origin (0,0) b) ordered pair c)Quadrants – counter clockwise 2.Graphing inequalities/abs and regions a) In which quadrants are x pos or neg? In which are y pos or neg? b) To graph inequalities, graph the line and pick a point to test

5 Distance Formula 1. d(a,b) = distance from point a to point b 2. Distance = √(x 1 – x 2 ) 2 + (y 1 – y 2 ) 2 This should be memorized; also on front cover of the text 3. Ex. The distance from (-3, 4) to (2, 7) is: √ (-3 – 2) 2 + (4 – 7) 2  √ (-5) 2 + (-3) 2  √  √ 34

6 Midpoint Formula 1.Midpt formula gives the coordinates (x,y) for the midpoint of a line segment 2. If a line segment has endpoints of (x 1, y 1 ) & (x 2,y 2 ), then the coordinates for the midpoint are: x= (x 1 +x 2 )/2 and y = (y 1 + y 2 )/2 Memorize; front cover of text

7 Midpoint Formula 3.Find the mdpt of the segment w/ endpoints of (5, 0) and (-4, 9): x-coordinate is: (5 + -4)/2  1/2 y-coordinate is: (0 + 9)/2  9/2 mdpt coordinates are (1/2, 9/2)


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