1. INTRODUCTION TO SPECTROSCOPY G. RAM KUMAR BY Department of Chemistry
Pydah College P.G. Courses

2. INTRODUCTION TO SPECTROSCOPY
It is the most powerful tool available for the study of atomic and molecular structures.
It is used in the analysis of wide range of samples.
What is spectroscopy?
Spectroscopy may be defined as the study of interactions between the matter and Electro Magnetic Radiations.

3. TYPES OF SPECTROSCOPY
Atomic Spectroscopy : It is concerned with interactions of Electro Magnetic Radiations with atoms.
Molecular Spectroscopy : It is concerned with interactions of
Electro Magnetic Radiations with molecules .
In general all the Spectroscopic methods are classified into two.
Non-Destructive methods Ex:UV-Visible , IR , NMR.
Destructive methods Ex:FES , AAS , ICP-MS.

4. ELECTROMAGNETIC RADIAIONS
Electromagnetic radiation is an oscillating electric and magnetic disturbance that spreads as a wave through empty space, the vacuum

5. Wave length(λ): It is the distance between two crests or troughs.
CHARACTERISTICS OF ELECTROMAGNETIC RADIATIONS
Wave length(λ): It is the distance between two crests or troughs.
Units: Å Angstroms or Nanometers nm
1 Å=10-8cm=10-10m
1nm=10 Å=10-9cm
Frequency(υ): It is defined as the number of waves which can pass through a point in one second.
Units: Hertz(Hz); Fresnel
1Hz = 1cycle/sec; 1Fresnel = Hz

6. Wave Number(ΰ): It is the reciprocal of wave length and is defined as the total number of waves which can pass through a space of 1cm.
Units: cm-1 or m-1
1cm-1 is sometimes called 1KAYSER(K)
Velocity(v): It is the distance travelled by a wave in 1sec.
Units: cm/sec or m/sec

7. DISPERSION OF LIGHT
When visible light (White light) is passed through prism, it split up into seven colors which corresponds to definite wave lengths.This is known as dispersion of light

9. Visible and Ultraviolet Spectroscopy

10. SPECTRUM:
The series of color bands obtained by dispersion of light is known as spectrum.
In a spectrum all these bands are arranged in the increasing order of wave length

11. CLASSIFICATION OF SPECTRA:
I 1.LINE SPECTRA : Spectrum obtained by interaction of electromagnetic radiations with atoms. Line spectra consists of sharp well defined lines that correspond to a definite frequency
2.BAND SPECTRA: Spectrum obtained by interaction of electromagnetic radiations with molecules.Band spectra consists of different bands just as visible spectrum.

12. II
CONTINUOUS SPECTRUM:
In a spectrum, if one color merges into another without a gap, then the spectrum is known as Continuous spectrum.
DISCONTINUOUS SPECTRUM:
In a spectrum , if one color will not merge into other is known as Discontinuous spectrum.

13. III
ABSORPTION SPECTRUM:
If the electromagnetic radiations are passed through a substance, the dark pattern of lines that are obtained corresponding to wave lengths absorbed is known as Absorption spectrum .
EMISSION SPECTRUM:
If electromagnetic radiations are passed through a substance, the pattern of lines recorded after the emission of the absorbed wave lengths are known as emission spectrum.

14. ELECTROMAGNETIC SPECTRUM
The arrangement of electromagnetic waves or radiations in the order of their increasing wave lengths or decreasing frequencies is called electromagnetic spectrum.

16. Interactions of Different types of Electromagnetic Radiations produce different types of Spectroscopy
Regions of EM spectrum
Radio frequency region
Microwave region
Infrared region
UV & Visible region
Type of sepctroscopy
Nuclear magnetic resonance or electron spin resonance
Rotational spectroscopy
Vibrational spectroscopy
Electronic spectroscopy

17. Electronic Excitation by UV/Vis Spectroscopy :
UV: valance
electronic excitation
Radio waves:
Nuclear spin states
(in a magnetic field)
IR: molecular vibrations
X-ray:
core electron
excitation

18. A=ebc The concentration dependence follows Beer’s Law.
The wavelength and amount of light that a compound absorbs depends on its molecular structure and the concentration of the compound used.
The concentration dependence follows Beer’s Law.
A=ebc
Where A is absorbance (no units, since A = log10 P0 / P )
e is the molar absorbtivity with units of L mol-1 cm-1
b is the path length of the sample - that is, the path length of the cuvette in which the sample is contained (typically in cm).
c is the concentration of the compound in solution, expressed in mol L-1

19. }  = hv Molecules have quantized energy levels:
ex. electronic energy levels. hv }
energy
energy

= hv
Q: Where do these quantized energy levels come from?
A: The electronic configurations of associated with bonding.
Each electronic energy level (configuration) has associated with it the many vibrational energy levels we examined with IR.

20. max = 135 nm (a high energy transition)
Absorptions having max < 200 nm are difficult to observe because everything (including quartz glass and air) absorbs in this spectral region.

21. = hv =hc/ Example: ethylene absorbs at longer wavelengths:
max = 165 nm = 10,000

22. The n to pi* transition is at even lower wavelengths but is not as strong as pi to pi* transitions. It is said to be “forbidden.”
Example:
Acetone: n max = 188 nm ; = 1860
n max = 279 nm ; = 15

23.  135 nm  165 nm n 183 nm weak  150 nm

24. 1,3 butadiene: max = 217 nm ; = 21,000
Conjugated systems:
Preferred transition is between Highest Occupied Molecular Orbital (HOMO) and Lowest Unoccupied Molecular Orbital (LUMO).
Note: Additional conjugation (double bonds) lowers the HOMO-LUMO energy gap:
Example:
1,3 butadiene: max = 217 nm ; = 21,000
1,3,5-hexatriene max = 258 nm ; = 35,000

25. Similar structures have similar UV spectra:
max = 240, 311 nm
max = 238, 305 nm
max = 173, 192 nm

26. For more than 4 conjugated double bonds:
Woodward-Fieser Rules for Dienes
  Homoannular Heteroannular
Parent l=253 nm l=214 nm
=217 (acyclic)
Increments for:
Double bond extending conjugation +30
  Alkyl substituent or ring residue +5
  Exocyclic double bond    +5
Polar groupings:
  -OC(O)CH3    +0
  -OR    +6
  -Cl, -Br   +5
  -NR
  -SR +30
exocyclic
Homoannular heteroannular acyclic
For more than 4 conjugated double bonds:
max = (# of alkyl groups) + n( n)

27. Parent: 202 (5-member ring ketone) +35 (alpha hydroxyl)
Parent: 214 (heteroannular)
3 alkyls +15 (3x5)
+5 (exocyclic)
TOTAL nm
(Actual = 235 nm)
Parent: 253 (homoannular)
3 alkyls +15 (3x5)
+5 (exocyclic)
TOTAL nm
(Actual = 275 nm)
Parent: (5-member ring ketone)
+35 (alpha hydroxyl)
+12 (beta alkyl - note part of ring)
Total: 249

28. max = (8) + 11*( *11) = 476 nm
max(Actual) = 474.