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Prepared by C P Prashanth KV Ganeshkhind Pune DISTINCTIONS BETWEEN SOME PAIRS OF ORGANIC COMPOUNDS (CHEMICAL TEST)

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Presentation on theme: "Prepared by C P Prashanth KV Ganeshkhind Pune DISTINCTIONS BETWEEN SOME PAIRS OF ORGANIC COMPOUNDS (CHEMICAL TEST)"— Presentation transcript:

1 Prepared by C P Prashanth KV Ganeshkhind Pune DISTINCTIONS BETWEEN SOME PAIRS OF ORGANIC COMPOUNDS (CHEMICAL TEST)

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9 C 2 H 5 Br + KOH (aq) → C 2 H 5 OH + KCl KCl + AgNO 3 → AgBr + KNO 3 Yellow ppt

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13 CH 3 —CH(Cl)—CH 3 + aqKOH → CH 3 —CH(OH)—CH 3 + NaOI → CHI 3 Isopropyl chloride i CH 3 CH 2 CH 2 C1 + aq KOH → CH 3 CH 2 CH 2 OH + NaOI →Does not give iodoform test.

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19 CH 3 CH 2 OH +I 2 /NaOH →CH 3 -CHO C 6 H 5 N 2 Cl + → C 6 H 5 -N=N- 3C 6 H 5 OH + FeCl 3 → (C 6 H 5 0) 3 Fe + 3HC1

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21 (iii) 3C 6 H 5 OH + FeCl 3 → (C 6 H 5 0) 3 Fe + 3HC1 C 6 H 5 N 2 Cl + → C 6 H 5 -N=N- + Br 2 →

22 1-Propanol (primary alcohol)does not produce turbidity at room temperature with Lucas reagent. CH 3 CH 2 CH 2 OH + anhyd ZnCl 2 + HCl → No turbidity at room 2-Methyl-2-propanol(tertiary alcohol) reacts with Lucas reagent (anhyd ZnCl 2 + HCl) giving turbidity immediately. (CH 3 ) 3 C-OH + anhyd ZnCl 2 + HCl → (CH 3 ) 3 C-Cl Turbidity immediately

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24 CH 3 —CH(CH3)—OH + 4I 2 + 6NaOH → CHI 3 + CH 3 COONa + 5NaI + 5H 2 0

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26 CH 3 CH(OH)CH 2 CH 3 + I 2 + NaOH → CHI 3 CH 3 CH 2 CH 2 CH 2 OH + I 2 + NaOH → No yellow ppt.

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45 3C 6 H 5 OH + FeCl 3 → (C 6 H 5 0) 3 Fe + 3HC1 Violet

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51 Primary amine can be tested by carbylamine test

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55 + NaOH →C 6 H 5 -NH 2 +C6H5-C6H5-

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57 → C 6 H 5 SO 2 N(CH 2 -CH 3 )2

58 Thanks C P Prashanth


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