Presentation is loading. Please wait.

Presentation is loading. Please wait.

© 2007 Pearson Education Learning Curve Analysis Supplement G.

Similar presentations


Presentation on theme: "© 2007 Pearson Education Learning Curve Analysis Supplement G."— Presentation transcript:

1 © 2007 Pearson Education Learning Curve Analysis Supplement G

2 © 2007 Pearson Education Learning Curves – – – – – – 0 0 – |||||| Learning curve Cumulative units produced Process time per unit (hr)

3 © 2007 Pearson Education Learning Curves – 0.25 – – – – – 0 0 – |||||| Learning curve Cumulative units produced Process time per unit (hr) Learning period Showing the learning period

4 © 2007 Pearson Education Learning Curves – – – – – – 0 0 – |||||| Learning curve Cumulative units produced Process time per unit (hr) Learning period Standard time Showing the learning period and the time when standards are calculated

5 © 2007 Pearson Education Developing Learning Curves  In developing learning curves we make the following assumptions:  The direct labor required to produce the n + 1 st unit will always be less than the direct time of labor required for the nth unit.  Direct labor requirements will decrease at a declining rate as cumulative production increases.  The reduction in time will follow an exponential curve. k n = k 1 n b where k 1 = direct labor hours for the 1 st unit n = cumulative number of units produced b = log r / log 2 r = learning rate

6 © 2007 Pearson Education 80% Conversion Factors for the Cumulative Average Number of Direct Labor Hours per Unit

7 © 2007 Pearson Education 90% Conversion Factors for the Cumulative Average Number of Direct Labor Hours per Unit

8 © 2007 Pearson Education Example G.1 Developing the 80% Learning Curve Manufacturer of diesel locomotives: Labor hours required for first unit = 50,000 Learning rate = 80% – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands)

9 © 2007 Pearson Education Example G.1 Estimating Direct Labor Requirements – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80%

10 © 2007 Pearson Education Example G.1 using the formula Labor hours required for 40 th unit k 40 = 50,000(40) (log 0.8)/(log 2) Labor hours required for first unit = 50,000 Learning rate = 80% – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands)

11 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) k 40 = 50,000(40) Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using the formula

12 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) k 40 = 50,000( ) Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using the formula

13 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) k 40 = 15,244 hours Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using the formula

14 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) k 40 = 15,244 hours Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using the formula

15 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) k 40 = 15,244 hours Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using the formula

16 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Cumulative average labor hours = Labor hours required for first unit = 50,000 Learning rate = 80% n % Learning Rate (n = cumulative production) Example G.1 using Conversion Factors

17 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Cumulative average labor hours = 50,000( ) n % Learning Rate (n = cumulative production) Example G.1 using Conversion Factors

18 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Cumulative average labor hours = 21,492 hours n % Learning Rate (n = cumulative production) Example G.1 using Conversion Factors

19 © 2007 Pearson Education Labor hours required for first unit = 50,000 Learning rate = 80% – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Example G.1 using Unit-doublings

20 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Example G.1 using Unit-doublings

21 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Second unit = 50,000(80%) Example G.1 using Unit-doublings

22 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Second unit = 40,000 hours Example G.1 using Unit-doublings

23 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Fourth unit = 40,000(80%) Example G.1 using Unit-doublings

24 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) Labor hours required for first unit = 50,000 Learning rate = 80% Fourth unit = 32,000 hours Example G.1 using Unit-doublings

25 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) The 80% Learning Curve for Example G.1

26 © 2007 Pearson Education – – – – – 0 0 – ||||||| Cumulative units produced Direct labor hours per locomotive (thousands) The 80% Learning Curve for Example G.1

27 © 2007 Pearson Education Application G.1 Estimating Direct Labor Requirements The 1 st unit of a new product is expected to take 1,000 hours. The learning rate is 80%, how much time should the 50 th unit take?

28 © 2007 Pearson Education Units perCumulative MonthMonthUnits Example G.2 Estimating Labor Requirements

29 © 2007 Pearson Education Example G.2 Estimating Labor Requirements Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units n % Learning Rate (n = cumulative production)

30 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,500 n % Learning Rate (n = cumulative production) Example G.2 Estimating Labor Requirements

31 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,035 n % Learning Rate (n = cumulative production) Example G.2 Estimating Labor Requirements

32 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 n % Learning Rate (n = cumulative production) Example G.2 Estimating Labor Requirements

33 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28, ,000( ) = 26, ,000( ) = 23, ,000( ) = 22, ,000( ) = 20,727 Example G.2 Estimating Labor Requirements

34 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26, ,000( ) = 23, ,000( ) = 22, ,000( ) = 20,727 Example G.2 Estimating Labor Requirements

35 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23, ,000( ) = 22, ,000( ) = 20,727 Example G.2 Estimating Labor Requirements

36 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Example G.2 Estimating Labor Requirements

37 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Month 1: Example G.2 Estimating Labor Requirements

38 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Month 1:57,000–0= 57,000 hours Example G.2 Estimating Labor Requirements

39 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Month 1:57,000–0= 57,000 hours Month 2:130,175–57,000= 73,175 hours Example G.2 Estimating Labor Requirements

40 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Month 1:57,000–0= 57,000 hours Month 2:130,175–57,000= 73,175 hours Month 3:239,830–130,175= 109,655 hours Month 4:400,032–239,830= 160,202 hours Month 5:621,810–400,032= 221,778 hours Example G.2 Estimating Labor Requirements

41 © 2007 Pearson Education Units perCumulative MonthMonthUnits Cumulative Average TimeTotal Hours Monthper Unitfor All Units 130,000( ) = 28,50028,500(2)=57, ,000( ) = 26,03526,035(5)=130, ,000( ) = 23,98323,983(10)=239, ,000( ) = 22,22422,224(18)=400, ,000( ) = 20,72720,727(30)=621,810 Month 1:57,000–0= 57,000 /150=380 employees Month 2:130,175–57,000= 73,175 /150=488 employees Month 3:239,830–130,175= 109,655 /150=731 employees Month 4:400,032–239,830= 160,202 /150=1068 employees Month 5:621,810–400,032= 221,778 /150=1479 employees Example G.2 Estimating Labor Requirements

42 © 2007 Pearson Education Application G.2 Estimating Cumulative Labor Hours An example of using the learning model to test budget constraints: A company has a contract to make a product for the first time. The total budget for the 38-unit job is 15,000 hours. The first unit took 1000 hours, and the rate of learning is expected to be 80 percent. Do you think the 38-unit job can be completed within the 15,000-hour budget? How many additional hours would you need for a second job of an 26 additional units?

43 © 2007 Pearson Education Application G.2 First 38-unit Job

44 © 2007 Pearson Education Application G.2 Second additional 26-unit Job


Download ppt "© 2007 Pearson Education Learning Curve Analysis Supplement G."

Similar presentations


Ads by Google