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Assignment: (2-12) B evens or odds AND (2-12) puzzle all Show all steps on graph paper in required format. Quiz corrections are due tomorrow for retakes. Math binder scores will be collected tomorrow for lessons #11- #21 10/21/08Solve with multiplication or division (2-12 B)#26 Warm-up: Solve the following A.B.C. D. x + 5 = 9 x – 34 = = x – 39 G.E.F.

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Assignment: (2-12) B evens or odds AND (2-12) puzzle all Show all steps on graph paper in required format. Quiz corrections are due tomorrow for retakes. Math binder scores will be collected tomorrow for lessons #11- #21 10/21/08Solve with multiplication or division (2-12 B)#26 Warm-up A.B.C. D. x + 5= 9 x – 34 = = x – 39 G. E. F. X = x = = x

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Like addition and subtraction, multiplication and division are inverse operations. They “undo” each other. ÷ Course Solving Equations by Multiplying or Dividing

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Solve the equation = 13. Check your answer. Additional Example 1: Solving an Equation by Multiplication h2h2 h2h2 = 13 h2h2 = 13(2) (2) h = 26 Check h2h2 = = 13 ? Think: h is divided by 2, so multiply both sides by 2 to isolate h. Substitute 26 for h. 26 is a solution. Course Solving Equations by Multiplying or Dividing 26 2 ? = 13

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You can multiply both sides of an equation by the same number, and the statement will still be true. 2 · 3 · 4 = 2 · 12 zx = zy 3 · 4 = 12 6 · 4 = 24 x = y If a variable is divided by a number, you can often use multiplication to isolate the variable. Multiply both sides of the equation by the number. MULTIPLICATION PROPERTY OF EQUALITY Course Solving Equations by Multiplying or Dividing

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Try This: Example 1 Insert Lesson Title Here Solve the equation = 30. Check your answer. x5x5 x5x5 = 30 x5x5 = 30(5) (5) x = 150 Check x5x5 = 30 Think: x is divided by 5, so multiply both sides by 5 to isolate x. 30 = 30 ? Substitute 150 for x. 150 is a solution ? = 30 Course Solving Equations by Multiplying or Dividing

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Solve the equation 51 = 17x. Check your answer. Additional Example 2: Solving an Equation by Division 51 = 17x 17 3 = x Check 51 = 17x Think: x is multiplied by 17, so divide both sides by 17 to isolate x. Substitute 3 for x. 3 is a solution. Course Solving Equations by Multiplying or Dividing 51 = 17(3) ? 51 = 51 ?

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You can divide both sides of an equation by the same nonzero number, and the statement will still be true. 5 · 6 = 30 5 · 6 3 = · 6363 = 10 5 · 2 = 10 xzxz x = y yzyz = z ≠ 0 You cannot divide by 0. Remember! DIVISION PROPERTY OF EQUALITY Course Solving Equations by Multiplying or Dividing

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Try This: Example 2 Insert Lesson Title Here Solve the equation 76 = 19y. Check your answer. 76 = 19y 19 4 = y Check 76 = 19y Think: y is multiplied by 19, so divide both sides by 19 to isolate y. Substitute 4 for y. 4 is a solution. Course Solving Equations by Multiplying or Dividing 76 = 19(4) ? 76 = 76 ?

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Beats in 10s times 6 = beats per minutes Additional Example 3 Continued b · 6 = 78 6b = 78 6 b = 13 Trevor’s heart beats 13 times 10 seconds. Think: b is multiplied by 6, so divide both sides by 6 to isolate b. Course Solving Equations by Multiplying or Dividing

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Lesson Quiz: Part 1 Solve the equation. Check your answer = 4x 2. 18z = = = 12y 5. z = 5 x = 3 Insert Lesson Title Here x = 48 y = 70 x4x4 h 22 = 9 h = 198 Course Solving Equations by Multiplying or Dividing

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Show all steps on graph paper in required format. (2-12) B evens or odds AND (2-12) puzzle all Quiz corrections are due tomorrow for retakes. Math binder scores will be collected tomorrow for lessons #11- #21 10/21/08Solve with multiplication or division (2-12 B)#26

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