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The Hamilton and Jefferson Method for Apportionment.

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Presentation on theme: "The Hamilton and Jefferson Method for Apportionment."— Presentation transcript:

1 The Hamilton and Jefferson Method for Apportionment

2 Ideal Ratio Example 1 A 989 B 855 C 694 D 462 If there are 30 seats to hand out then the ideal ratio would be found by

3 Quotas Each class size divided by the ideal ratio. Example 1 A 989 B 855 C 694 D 462 A = 989 ÷ 100 = 9.89 B = 855 ÷ 100 = 8.55 C = 694 ÷ 100 = 6.94 D = 462 ÷ 100 = 4.62

4 Hamilton Initial Distribution Class sizeQuotaTrunc A B C D Truncate the quotas to find the starting place.

5 Hamilton Final Distribution Class sizeQuotaTruncHamilton A B C D The remaining seats go to the class with the largest decimal part of the quota. With each class getting at most one additional seat

6 Jefferson Meathod Instead of giving the remaining seats to the class with the largest decimal part. Find how many people each representative will represent. Do this by finding the Jefferson adjusted ratio.

7 Jefferson Initial Distribution Class sizeQuotaTruncJ.A.R. A ÷ B ÷995 C ÷ D ÷ Divide each class size by one more than the trunc

8 Jefferson Final Distribution Class sizeQuotaTruncJ.A.R. Jefferson A B C D Give the class with an adjusted ratio that is the closest to the ideal ratio gets the first additional seat. Calculate another adjusted rate for that class and use this new A.R. to help determine who gets any additional seats. A class may get more than one additional seat.


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