Download presentation

Presentation is loading. Please wait.

Published bySydney Manning Modified over 3 years ago

1
Chapter 12 Sorting and searching

2
This chapter discusses n Two fundamental list operations. u Sorting u Searching n Sorted lists. n Selection/bubble sort. n Binary search. n Loop invariant.

3
Ordering lists n There must be a way of comparing objects to determine which should come first. There must be an ordering relation. n There must be an operator to compare the objects to put them in order. n The ordering is antisymmetric. (a b !
{
"@context": "http://schema.org",
"@type": "ImageObject",
"contentUrl": "http://images.slideplayer.com/1/245083/slides/slide_3.jpg",
"name": "Ordering lists n There must be a way of comparing objects to determine which should come first.",
"description": "There must be an ordering relation. n There must be an operator to compare the objects to put them in order. n The ordering is antisymmetric. (a b !

4
Implementing comparison public boolean lessThan (Student s) s1.lessThan(s2) Returns true if s1 =s2. for i > 0, j < size(), get(i).lessThan(get(j)) implies i < j.

5
Selection Sort n Find the smallest element in the list, and put it in first. n Find the second smallest and put it second, etc.

6
Selection Sort (cont.) n Find the smallest. n Interchange it with the first. n Find the next smallest. n Interchange it with the second.

7
Selection Sort (cont.) n Find the next smallest. n Interchange it with the third. n Find the next smallest. n Interchange it with the fourth.

8
Selection Sort (cont.) n To interchange items, we must store one of the variables temporarily.

11
Analysis of selection sort n If there are n elements in the list, the outer loop is performed n-1 times. The inner loop is performed n-first times. i.e. time= 1, n-1 times; time=2, n-2 times; … time=n-2, 1 times. n (n-1)x(n-first) = (n-1)+(n-2)+…+2+1 = (n 2 -n)/2 n As n increases, the time to sort the list goes up by this factor (order n 2 ).

12
Bubble sort n Make a pass through the list comparing pairs of adjacent elements. n If the pair is not properly ordered, interchange them. n At the end of the first pass, the last element will be in its proper place. n Continue making passes through the list until all the elements are in place.

13
Pass 1

14
Pass 1 (cont.)

15
Pass 2

16
Pass 3 &4

18
Analysis of bubble sort n This algorithm represents essentially the same number of steps as the selection sort. n If make a pass through the list without interchanging, then the list is ordered. This makes the algorithm fast if it is mostly ordered.

21
Binary search n Assumes an ordered list. n Look for an item in a list by first looking at the middle element of the list. n Eliminate half the list. n Repeat the process.

22
Binary search

23
private int itemIndex (Student item, StudentList list) The proper place for the specified item on the specified list, found using binary search. require: list is sorted in increasing order ensure: 0 <= result <= list.size() for 0 <= i < result list.get(i) < item for result <= i < list.size() list.get(i) >= item

24
Binary search (cont.) private int itemIndex (Student item, StudentList list) { int low; //lowest index considered int high; //highest index considered int mid; //middle between high and low low =0 high = list.size() -1; while (low <= high) { mid = (low+high)/2; if (list.get(mid).lessThan(item)) low = mid+1; else high = mid-1; } return low; }

25
Binary search (cont.)

26
Completing the search /** * Uses binary search to find where and if an element * is in a list. * require: * item != null * ensure: *if item == no element of list * indexOf(item, list) == -1 *else * item == list.get(indexOf(item, list)), * and indexOf(item, list) is the smallest * value for which this is true */ public int indexOf(Student item, StudentList list){ int i = itemIndex(item, list); if (i

27
Sequential/linear search public int indexOf (Student obj) { int i; int length; length = this.size(); i = 0; while (i < length && !obj.equals(get(i))) i = i+1; if ( i < length) return i; else return -1;// item not found }

28
Relative efficiency

29
Loop invariant n A loop invariant is a condition that remains true as we repeatedly execute the loop body, and captures the fundamental intent in iteration. n partial correctness: the assertion that a loop is correct if it terminates. n total correctness: the assertion that a loop is both partially correct, and terminates. n loop invariant: a condition that is true at the start of execution of a loop and remains true no matter how many times the body of the loop is performed.

30
Back to binary search 1.private int itemIndex (Student item, StudentList list) { 2.low =0 3.high = list.size() -1; 4.while (low <= high) { 5.mid = (low+high)/2; 6. if (list.get(mid).lessThan(item)) 7. low = mid+1; 8. else 9. high = mid-1; 10.} 11.return low; 12.} n At line 6, we can conclude 0 <= low <= mid <= high < list.size()

31
The key invariant for 0 <= i < low list.get(i) < item for high < i < list.size() list.get(i) >= item n This holds true at all four key places (a, b, c, d). u It is vacuously true for indexes less than low or greater than high (a) u We assume it holds after merely testing the condition (b) and (d) u If the condition holds before executing the if statement and the list is sorted in ascending order, it will remain true after executing the if statement (condition c).

32
The key invariant n We are guaranteed that for 0 <= i < mid list.get(i) < item After the assignment, low equals mid+1 and so for 0 <= i < low list.get(i) < item n This is true before the loop body is done: for high < i < list.size( list.get(i) >= item

33
Partial correctness: If the loop body is not executed at all, and point (d) is reached with low == 0 and high == -1. If the loop body is performed, at line 6, low <= mid <= high. low <= high becomes false only if mid == high and low is set to mid + 1 or low == mid and high is set to mid - 1 In each case, low == high + 1 when the loop is exited.

34
Partial correctness: n The following conditions are satisfied on loop exit low == high + 1 for 0 <= i <= low list.get(i) < item for high < i < list.size() list.get(i) >= item n which implies for 0 <= i < low list.get(i) < item for low <= i < list.size() list.get(i) >= item

35
Loop termination When the loop is executed, mid will be set to a value between high and low. The if statement will either cause low to increase or high to decrease. This can happen only a finite number of times before low becomes larger than high.

36
Weve covered n Sorting u selection sort u bubble sort n Searching u Sequential/linear search u binary search n Verifying correctness of iterations u partial correctness u loop invariant u key invariant u termination

37
Glossary

38
Glossary (cont.)

Similar presentations

OK

Selection Sort 345012 641532. 345012 6 41532 345012 64 1532.

Selection Sort 345012 641532. 345012 6 41532 345012 64 1532.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on event handling in javascript which term Ppt on computer languages history Ppt on conference call etiquette video Ppt on nitrogen cycle and nitrogen fixation bacteria Ppt on saving natural resources Ppt on transformational leadership theory Ppt on 2nd world war year Ppt on palliative care pain management end of life care Ppt on telephone etiquettes and manners Ppt on minerals and energy resources for class 10 free download