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Lesson Starter Write the stock system names for MnO, PbO 2 Write the stock system names for MnO, PbO 2 Manganese (II) Oxide Manganese (II) Oxide Lead (IV) Oxide Lead (IV) Oxide

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How would you find the mass of the system if they could not measure it as a whole ?

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Formula Weights and Percentage Composition Section 3.3

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Three Concepts Formula Mass Formula Mass Molar Mass Molar Mass Percentage Composition Percentage Composition

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Formula Mass The sum of the average atomic masses represented by the formula. The sum of the average atomic masses represented by the formula. H 2 0 as an example H 2 0 as an example 2 atoms of H 1 atom of O 1.01 amu x H atom = 2.02 amu 16.00 amu x O atom = 16.00 amu 18.02 amu

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Formula Mass NaCl NaCl H 2 SO 4 H 2 SO 4 MgCl 2 MgCl 2 HCl HCl 58.44 amu 58.44 amu 98.09 amu 98.09 amu 95.21 amu 95.21 amu 36.46 amu 36.46 amu

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Molar Mass The mass in grams of 1 mole or 6.022 x 1023 particles. (same number as formula mass) H20 as an example 2 moles of H 1 mole of O 1.01 g x H mole = 2.02 g 16.00 g x O mole = 16.00 g 18.02 g/mol

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Molar Mass NaCl NaCl H 2 SO 4 H 2 SO 4 MgCl 2 MgCl 2 HCl HCl 58.44 g/mol 58.44 g/mol 98.09 g/mol 98.09 g/mol 95.21 g/mol 95.21 g/mol 36.46 g/mol 36.46 g/mol

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Percentage Composition (% Comp) The % by mass of each element in a compound. (FORMULA ON pg. 88) The % by mass of each element in a compound. (FORMULA ON pg. 88) Find the percentage composition of water. 2 moles of H 1 mole of O 1.01 g x H mole = 2.02 g 16.00 g x O mole = 16.00 g 18.02 g/mol

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Percentage Composition Find the percentage composition of water. 2.02 g H 16.00 g O 18.02 g H 2 O x 100% = 11.21% H 18.02 g H 2 O x 100% = 88.79 % O

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Practice Find the percentage compositions of: Find the percentage compositions of: Ba(NO 3 ) 2 Ba(NO 3 ) 2 PbCl 2 PbCl 2

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Ba(NO 3 ) 2 Ba(NO 3 ) 2 1 mol Ba X137.33 g/ mol Ba = 137.33 g Ba 2 mol N X14.00 g/ mol N = 28.00 g N 6 mol O X16.00 g/ mol O = 96.00 g O 261.33 g total

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137.33 g Ba 28.00 g N 96.00 g O 261.33 g total X 100 = 261.33 g total X 100 = 261.33 g total X 100 = 52.6 % Ba 10.7 % N 36.7 % O

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PbCl 2 PbCl 2 1 mol Pb X207.2 g/ mol Pb = 207.2 g Pb 2 mol Cl X35.45 g/ mol Cl = 70.9 g Cl 278.1 g total

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X 100 = 74.5 % Pb 25.5 % Cl 278.1 g total 207.2 g Pb 70.9 g Cl

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Homework Page 110 Page 110 3.21 3.21 3.23 3.23

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