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Lesson Starter Write the stock system names for MnO, PbO 2 Write the stock system names for MnO, PbO 2 Manganese (II) Oxide Manganese (II) Oxide Lead.

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Presentation on theme: "Lesson Starter Write the stock system names for MnO, PbO 2 Write the stock system names for MnO, PbO 2 Manganese (II) Oxide Manganese (II) Oxide Lead."— Presentation transcript:

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2 Lesson Starter Write the stock system names for MnO, PbO 2 Write the stock system names for MnO, PbO 2 Manganese (II) Oxide Manganese (II) Oxide Lead (IV) Oxide Lead (IV) Oxide

3 How would you find the mass of the system if they could not measure it as a whole ?

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5 Formula Weights and Percentage Composition Section 3.3

6 Three Concepts Formula Mass Formula Mass Molar Mass Molar Mass Percentage Composition Percentage Composition

7 Formula Mass The sum of the average atomic masses represented by the formula. The sum of the average atomic masses represented by the formula. H 2 0 as an example H 2 0 as an example 2 atoms of H 1 atom of O 1.01 amu x H atom = 2.02 amu amu x O atom = amu amu

8 Formula Mass NaCl NaCl H 2 SO 4 H 2 SO 4 MgCl 2 MgCl 2 HCl HCl amu amu amu amu amu amu amu amu

9 Molar Mass The mass in grams of 1 mole or x 1023 particles. (same number as formula mass) H20 as an example 2 moles of H 1 mole of O 1.01 g x H mole = 2.02 g g x O mole = g g/mol

10 Molar Mass NaCl NaCl H 2 SO 4 H 2 SO 4 MgCl 2 MgCl 2 HCl HCl g/mol g/mol g/mol g/mol g/mol g/mol g/mol g/mol

11 Percentage Composition (% Comp) The % by mass of each element in a compound. (FORMULA ON pg. 88) The % by mass of each element in a compound. (FORMULA ON pg. 88) Find the percentage composition of water. 2 moles of H 1 mole of O 1.01 g x H mole = 2.02 g g x O mole = g g/mol

12 Percentage Composition Find the percentage composition of water g H g O g H 2 O x 100% = 11.21% H g H 2 O x 100% = % O

13 Practice Find the percentage compositions of: Find the percentage compositions of: Ba(NO 3 ) 2 Ba(NO 3 ) 2 PbCl 2 PbCl 2

14 Ba(NO 3 ) 2 Ba(NO 3 ) 2 1 mol Ba X g/ mol Ba = g Ba 2 mol N X14.00 g/ mol N = g N 6 mol O X16.00 g/ mol O = g O g total

15 g Ba g N g O g total X 100 = g total X 100 = g total X 100 = 52.6 % Ba 10.7 % N 36.7 % O

16 PbCl 2 PbCl 2 1 mol Pb X207.2 g/ mol Pb = g Pb 2 mol Cl X35.45 g/ mol Cl = 70.9 g Cl g total

17 X 100 = 74.5 % Pb 25.5 % Cl g total g Pb 70.9 g Cl

18 Homework Page 110 Page


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