Presentation is loading. Please wait.

Presentation is loading. Please wait.

Mole relationships in chemical equations. DO-NOW – Silent and Independent!  Remember:  (g) = gas (l) = liquid (s) = solid  (aq) = aqueous  Must use.

Similar presentations


Presentation on theme: "Mole relationships in chemical equations. DO-NOW – Silent and Independent!  Remember:  (g) = gas (l) = liquid (s) = solid  (aq) = aqueous  Must use."— Presentation transcript:

1 Mole relationships in chemical equations

2 DO-NOW – Silent and Independent!  Remember:  (g) = gas (l) = liquid (s) = solid  (aq) = aqueous  Must use rules for naming/writing formulas  Ionic compounds – balance charges, NO prefixes  Covalent compounds – use prefixes

3 Information from Chemical Equations  To produce fertilizers, Nitrogen gas is combined with Hydrogen gas to produce Nitrogen trihydride (ammonia).  N 2 (g) + H 2 (g)  NH 3 (g)

4 Information from Chemical Equations  Making fertilizer uses a lot of energy and a lot of raw materials  Efficiency is key!!  How can knowledge about chemical reactions make This process as efficient as possible?

5 The Law of Conservation of Mass  In a chemical reaction, matter is never created or destroyed.  The number of atoms and the mass of the reactants must be equal to the number of atoms and the mass of the products.

6 Mini-Lab!  NaHCO 3 (s) + CH 3 COOH(aq)  CO 2 (g) + H 2 O(l) + NaCO 3 (aq)  Baking soda reacts with acetic acid (vinegar) to produce…  Carbon dioxide gas, liquid water, and sodium carbonate solution Initial mass: Final mass:

7 Mini - Lab 1. Find the mass of both reagents IN THEIR CONTAINERS. 2. Record this mass as your initial mass 3. Remove materials from balance 4. Carefully pour the acetic acid into the baking soda. Agitate until bubbling stops 5. Find the mass of both reagents IN THEIR CONTAINERS again. 6. Record this mass as your final mass

8 What were your results?  Thoughts? Why doesn’t this reaction seem to obey the law of conservation of mass?  What could we do to confirm that it satisfies the law of conservation of mass?

9 More examples: Law of Conservation of Mass  CS 2 (l) + O 2 (g)  CO 2 (g) + SO 2 (g)  If I reacted 5 grams of CS 2 with 5 grams of O 2, and the reaction produced 2 grams of CO 2, how many grams of SO 2 must have been produced?  If my products had a total mass of 20 grams, how many grams of reactants must I have started with?  If I reacted 3 grams of CS 2 with an unknown number of grams of O 2 and produced a total of 4 grams of products, what was the mass of the O2?

10 Balancing Chemical Equations  How do we show, in a chemical equation, that the law of conservation of mass is being obeyed?  The law of conservation of mass must be satisfied by equalizing the number of atoms on the reactant and the product sides.  Use coefficients to show how many molecules of each compound.

11  H 2 (g) + F 2 (g)  HF(g) H 2 (g) + F 2 (g)  HF(g) 2

12 Rules for balancing an equation 1. Only 1. Only change the coefficients that appear in front of an element or compound 2. Never subscripts 2. Never change any subscripts in a formula 3. Coefficients should be written as the lowest possible ratios 4. Begin by balancing elements that appear ONLY once on each side of the equation

13  H 2 O(l)  H 2 (g) + O 2 (g) H 2 O(l)  H 2 (g) + O 2 (g) 22

14 Balancing Chemical Equations  Ca(s) + S 8 (s)  CaS(s) Ca(s) + S 8 (s)  CaS(s) 8 8

15  Zn(s) + HCl(aq)  ZnCl 2 (aq) + H 2 (g) Zn(s) + HCl(aq)  ZnCl 2 (aq) + H 2 (g) 2

16 Na 2 O 2 + H 2 O  NaOH + O 2

17 2Na 2 O 2 + 2H 2 O  4NaOH + O 2

18 CaCl 2 + Fe 2 (SO 4 ) 3  CaSO 4 + FeCl 3

19 3CaCl 2 + Fe 2 (SO 4 ) 3  3CaSO 4 + 2FeCl 3

20  Liquid silicon tetrachloride reacts with liquid water to produce solid silicon dioxide and a solution of hydrochloric acid (HCl).  Write the chemical equation for this word equation  Balance it

21  SiCl 4 (l) + 2H 2 O(l)  SiO 2 (s) + 4HCl(aq)

22 Mole Ratios in Chemical Equations

23 Building a Tricycle  To build a tricycle, you need a frame, a seat, 3 wheels, a set of handlebars and 2 pedals  If I wanted to build 2 tricycles,  How many seats would I need?  How many wheels?  What if I wanted 346 tricycles?

24 Balanced Chemical Equations  Chemical equations are our recipes for chemical reactions!  Balanced chemical equations can be used to calculate how much reactant we will use or how much product is formed from a chemical reaction

25  Coefficients indicate relative numbers of moles or molecules of reactants and products.  H 2 (g) + Cl 2 (g)  2HCl(g)  One mole of hydrogen reacts with one mole of chlorine gas to yield two moles of hydrogen chloride gas. OR:  One molecule of hydrogen gas reacts with one molecule of chlorine gas to yield two molecules of hydrogen chloride gas.

26 N 2 (g) +3H 2 (g)  2NH 3 (g)  Number of Molecules – look at coefficients:  1 molecule of N2  3 molecules of H2  2 molecules of NH3  Just like with atoms, it makes more practical sense to use Avogadro's number (1 mole) of molecules rather than individual molecules

27 N 2 (g) +3H 2 (g)  2NH 3 (g)  Number of Moles – look at coefficients:  1 mole of N2  3 moles of H2  2 moles of NH3  Note that the number of moles (like the number of molecules) is not the same on both sides!

28 Na 2 O(s) + 2CO 2 (g) + H 2 O(g)  2NaHCO 3 (s)  How many moles of sodium oxide?  How many moles of carbon dioxide?  How many moles of water vapor?  How many moles of sodium hydrogen carbonate?

29

30 Mole Ratios  What is the RATIO between tricycle seats and tricycle wheels?  1 seat : 3 wheels  1 seat 3 wheels Using the fractional form of the ratio is going to make a lot more sense in chemistry

31 Mole Ratios N 2 (g) +3H 2 (g)  2NH 3 (g) What are the mole ratios between: moles of N2 and moles of H2? moles of NH3 and moles of N2? moles of H2 and moles of NH3? 1mol N2 2mol NH3 3mol H2 3mol H2 1mol N2 2mol NH3

32 2H 2 O(l)  2H 2 (g) + O 2 (g)  How many moles of water?  How many moles of oxygen gas?  How many moles of hydrogen gas?  Mole ratio of water to hydrogen gas.  Mole ratio of oxygen gas to hydrogen gas.

33 CS 2 (l) + 3O 2 (g)  CO 2 (g) + 2SO 2 (g)  How many moles of oxygen gas?  How many moles of carbon dioxide gas?  Mole ratio of oxygen to carbon dioxide.  Mole ratio of carbon disulfide to oxygen.  Mole ratio of carbon dioxide to sulfur dioxide.

34 4Fe(s) + 3O 2 (g)  2Fe 2 O 3 (s)  Mole ratio of iron to oxygen gas.  Mole ratio of oxygen gas to iron (III) oxide.  Mole ratio of iron (III) oxide to iron.

35

36 N 2 (g) +3H 2 (g)  2NH 3 (g)  How many moles of ammonia will I get by reacting 2 moles of nitrogen gas? 2mol N2 x 2 mol NH3 = 4 mol NH3 1 1 mol N2 The ONLY way to relate amounts of two different substances is to use the MOLE RATIO!! GIVEN MOLE RATIO

37 To get from moles of substance A to moles of substance B, always use the mole ratio! STEP 1: Write the given value (with a unit) over 1 STEP 2: Write a blank conversion factor STEP 3: Fill in the units to cancel your given unit STEP 4: Complete the mole ratio STEP 5: Multiply/Divide to get final answer MOLE  MOLE conversions

38 N 2 (g) +3H 2 (g)  2NH 3 (g) How many moles of nitrogen gas react with 12 moles of hydrogen gas? 12 mol H2 x 1 mol N2 = 4 mol N2 1 3 mol H2 The ONLY way to relate amounts of two different substances is to use the MOLE RATIO!! GIVENMOLE RATIO

39 4Fe(s) + 3O 2 (g)  2Fe 2 O 3 (s)  How many moles of oxygen gas react with 4 moles of solid iron?  How many moles of iron (III) oxide are produced by the reaction of 3 moles of oxygen gas?  How many moles of solid iron are required to react with 3 moles of oxygen gas?  How many molecules of iron (III) oxide are produced by the reaction of 4 molecules of solid iron?

40 CS 2 (l) + 3O 2 (g)  CO 2 (g) + 2SO 2 (g)  How many molecules of CS 2 react with 9 molecules of O 2 ?  How many molecules of O 2 react with 2 molecules of CS 2 ?  How many moles of CO 2 are produced by the reaction of 3 moles of CS 2 ?  How many moles of SO 2 are produced by the reaction of 12 moles of O 2 ?


Download ppt "Mole relationships in chemical equations. DO-NOW – Silent and Independent!  Remember:  (g) = gas (l) = liquid (s) = solid  (aq) = aqueous  Must use."

Similar presentations


Ads by Google