1. Lauren Byrd, Casey Craig, and Harper Curry Pre-Ap Geometry – 6 th period March 9, 2009

2. 30 Degrees! 40 ft. 30⁰ 59.5cm Long Leg=√3(short leg) 40=√3(short leg) 40/√3=short leg Short leg=23.09+5.2 Height of goal post= 28.29 tan30=short leg/40 (40)tan30=short leg/30 (40) Short leg=23.09+5.2 Height of goal post= 76.82 Lauren

3. 60 Degrees! 60 º 30 feet Long Leg= Short Leg ( √ 3) Long Leg = 30 √3 Long Leg = 51.96 Long Leg + Person’s Height = Goal Post 51.96 +5.2= Goal Post Height Height of Goal Post = 111.46 Lauren 60 º Tan(60) = opposite (adjacent) Tan (60) = o (30) Tan 60/30 = o Long Leg = 51.96 Long Leg + Person’s Height = Goal Post Height 51.96+59.5 = Goal Post Height 111.46 = Height of Goal Post 59.5 cm

4. 45 Degrees! 45 º Casey Leg = leg 24 = 24 Leg + person’s height= height of goal post 24 + 5.7 = height of goal post Height of goal post = 29.7 Tan 45 = leg/24Leg + height=goal post height 24 (tan 45) = leg24 + 5.7 = goal post height Leg = 24goal post height = 29.7

5. 25 Degrees! 36 feet 25⁰ 65 ° Harper Tan 25 = short leg/ 36short side + height = height of goal post 36 (tan25) = short side16.79+5.4 = goal post height Short side = 16.79goal post height = 21.94

6. Conclusion The average height of the goal post is 34.27 feet Lesson’s Learned – The length of the long leg gets bigger as the angle measure gets smaller – The height of the goal post was inconsistant in all of the triangles.