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Published byAbigail Debell Modified over 4 years ago

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By Will Henson, Keighly Laney,and Tori Gaston March 9, 2009 6 th Period

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Tori Gaston 42 feet from base Eye height: 58in Tanx =opp. adj. Tan 10= x 42 42 (tan10)= x x≈7.41 X ≈ 7.41feet+58in x ≈ 7.41feet+4.83 feet x≈12.24 10 )

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Will Henson 18 feet from base Eye height: 61.5inches Tan x= opp adj Tan 30= x 18 x≈10.39ft x≈10.39ft+ 61.5in x≈10.39ft+ 5.13ft x≈15.52 feet Long leg= √3 short leg 18=√3short leg 18/√3= short leg Short leg=6√3 X≈ 10.39+5.13 x≈15 0r 6√3 + 5.13 30 )

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Keighly Laney 10 feet from base Eye height: 58inches 45 ) Short leg=short leg 10=10 10 + 58in 10 + 4.83 X ≈ 10.48 Tan45= x 10 x= 10 10 + 58in 10ft + 4.83ft x= 14.83feet

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Will Henson 4 feet from base Eye height: 61.5inches 60 ) Tan= opp adj Tan60= x 4 x ≈ 6.93 6.93 + 61.5in 6.39 + 5.13ft x≈11.53feet Long leg= √3short leg x= (√3) 4 x= 4√3 4√3ft + 61.5in 4√3ft + 5.13ft 93ft + 5.13ft = 12.06ft x ≈ 12.06feet or 4√3 + 5.13feet

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The average height of the foul pole for this project was 13.17 feet tall. To find the height of the foul pole, each member of the group counted the distance from the foul pole at 10 ⁰, 30 ⁰, 45 ⁰, and 60 ⁰. We then used trigonometry and special right triangles. We used the distance from the base as one of the legs. For the special right triangles, we used a clinometer to measure the degrees. One lesson I learned from this project is that the shorter the distance from the base, the greater the angle degree is.

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