# Position-Time Graphs. POSITION (m) TIME (s) 10 20 30 40 50 5 10 1520 25 0 0 v = v = 2 m/s [E] 50 - 30 25 - 15 v = Δd Δt v = 35 - 15 17.5 - 7.5.

## Presentation on theme: "Position-Time Graphs. POSITION (m) TIME (s) 10 20 30 40 50 5 10 1520 25 0 0 v = v = 2 m/s [E] 50 - 30 25 - 15 v = Δd Δt v = 35 - 15 17.5 - 7.5."— Presentation transcript:

Position-Time Graphs

POSITION (m) TIME (s) 10 20 30 40 50 5 10 1520 25 0 0 v = v = 2 m/s [E] 50 - 30 25 - 15 v = Δd Δt v = 35 - 15 17.5 - 7.5

+ 3.8 m/s v = + 6.7 m/s v = v = ∆d t POSITION (m) TIME (s) 5 10 15 20 1 2 34 The steeper the line on a P-T graph, the greater the magnitude (size) of the velocity for that interval.

Relating P-T graphs to Velocity I don't like you. Good.

Origin - + P(m) T(s) P - T Graph + slope Straight line Moderate slope Positive slope Uniform velocity Slow velocity Moving away to the right d1d1 d2d2 10 0

Origin - + P(m) T(s) P - T Graph + slope Straight line Steep slope Positive slope Uniform velocity Fast velocity Moving away to the right d1d1 d2d2

Origin - + P(m) T(s) P - T Graph No change in position No velocity (Uniform) d1d1 NO slope

P - T Graph Origin - + P(m) T(s) - slope Straight line Moderate slope Negative slope Uniform velocity Slow velocity Moving towards the left d1d1 d2d2

Origin - + P - T Graph P(m) T(s) - slope Straight line Steep slope Negative slope Uniform velocity Fast velocity Moving towards the left d1d1 d2d2

P(m) T(s) P - T Graph - slope Origin - + Straight line Steep slope Negative slope Uniform velocity Fast velocity Moving left and passing d1d1 d2d2 0 +30 -5

Position (m) Time (s) 0 +35 30 25 20 15 10 5 5 -10 ∆d = 5 + 15 + 5 = 25 m ∆d = d 2 – d 1 = (+15) – (0) = +15 m

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