Download presentation

Presentation is loading. Please wait.

Published byAdrian Woodward Modified over 4 years ago

1
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Molar heat of combustion = ?

2
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 ?

3
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 X

4
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270. Moles fuel = 1.34 / 56.4 = 0.023 Molar heat of combustion = 6270 / 0.023 = 272.6 NO UNITS

5
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270 J Moles fuel = 1.34 / 56.4 = 0.023 mol Molar heat of combustion = 6270 / 0.023 mol = 272.6 kJ mol -1 ?

6
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100 x 15 x 4.18 = 6270 J Moles fuel = 1.34 / 56.4 = 0.023 mol Molar heat of combustion = 6270 / 0.023 mol = 263.9 kJ mol -1 STILL NO UNITS X

7
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 272.6 kJ mol -1 ?

8
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 272.6 kJ mol -1 Wrong Significant Figures X

9
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 273 kJ mol -1 ?

10
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 = 0.023 mol Molar heat of combustion = 6270 J / 0.023 mol = 264 kJ mol -1 Rounded before the end X

11
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 Molar heat of combustion = 6270 J = 264 kJ mol -1 1.34g / 56.4 g mol -1 ?

12
Heat of Combustion Mass of water = 100g Temp rise of water = 15.0 C Mass of fuel used = 1.34g Molar mass of fuel = 56.4 g mol -1 Energy (Q) = mc T C = 4.18 J g -1 K -1 Energy absorbed by water (Q) = 100g x 15K x 4.18Jg -1 K -1 = 6270 J Moles fuel = 1.34g / 56.4 g mol -1 Molar heat of combustion = 6270 J = 264 kJ mol -1 1.34g / 56.4 g mol -1 Much Better !

Similar presentations

Presentation is loading. Please wait....

OK

CALCULATIONS INVOLVING COLLIGATIVE PROPERTIES

CALCULATIONS INVOLVING COLLIGATIVE PROPERTIES

© 2018 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on mobile and wireless networks Ppt on next generation 2-stroke engine pistons Ppt on statistics and probability books Ppt on marketing strategy of nokia and samsung Ppt on metro bridge construction Ppt on biotics supplements Ppt on automobile related topics about information Ppt on 3-phase squirrel cage induction motor Ppt on any business plan Ppt on water pollution for class 9