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Published byDarnell Booker Modified over 2 years ago

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PROJECT TEAMS A 1 & 2 B 6 & 15 C 4 & 5 D 3 & 7 E 8 & 14 F 12 & 13 G 9 & 16 H 10 & 11

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4.69 k COM VV 10A mA A A V dc R 2 = 4.69 10 3

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Power supply (“battery”) variable fixed 241068 5.20 V COM VV 10A mA A A V dc = 5.20 V

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1Check all leads for low resistance (R setting on multimeter) 2Measure resistance values for 1.0 K and 4.7 K resistors (R on multimeter) 3Check power supply is ok – fixed & variable (V setting on multimeter) 4Start on experiment – measurement of resistance current I (1 A = 10 3 mA amperes, milliamperes) Voltage V (V volts) battery voltage emf Resistance R ( ohms) I = V / R V = I R R series = R 1 + R 2 R parallel = 1/(1/R 1 + 1/R 2 )) Kirchhoff’s voltage law: loop = loop V Kirchhoff’s current law: junction I = 0 All measurements (name) symbol = value unit V 1 = 4.5 V I 1 = 125 mA

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ADDING INTEGERS 1. POS. + POS. = POS. 2. NEG. + NEG. = NEG. 3. POS. + NEG. OR NEG. + POS. SUBTRACT TAKE SIGN OF BIGGER ABSOLUTE VALUE.

ADDING INTEGERS 1. POS. + POS. = POS. 2. NEG. + NEG. = NEG. 3. POS. + NEG. OR NEG. + POS. SUBTRACT TAKE SIGN OF BIGGER ABSOLUTE VALUE.

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