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Answers to Station #1 Word Problems One number is 36 less than another. Together both numbers total 90. What is each number? 1 st Number = x 2 nd Number = x – 36 Equation is…..x + x – 36 = 90 x + x – 36 = 90 2x – 36 = x = x = 63 The 1st number is 63 and the 2 nd number is 27. Timmy has $52 more than Johnny. Together they have $160. How much does each have? Johnny = J Timmy = J + 52 Equation is…..J + J + 52 = 160 J + J + 52 = 160 2J + 52 = J = J = 54 Johnny has $54.00 and Timmy has $

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Answers to Station #2 Word Problems The sum of two numbers is 82. The larger number is one more than twice the smaller number. Find the numbers. Smaller number = s Larger number = 2s + 1 Equation…..s + 2s + 1 = 41 s + 2s + 1 = 41 3s + 1 = s = s = 13.3 The smaller number is 13.3 and the larger number is Ida Claire is six times as old as Claire Fie. The sum of their ages is 77 years. Find the age of each. Claire Fie = f Ida Claire = 6f Equation…..f + 6f = 77 f + 6f = 77 7f = f = 11 Ida Claire is 11 years old and Ida Claire is 66 years old.

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Answers to Station #3 Word Problems The length of a rectangle is equal to three the width. The perimeter of the rectangle is 156 inches. What is the width of the rectangle? width = w length = 3w Equation…..w + 3w = 156 w + 3w = 156 4w = w = 39 The width of the rectangle is 39 inches and the length is 117 inches. The sum of two consecutive numbers is 415. What are the numbers? 1 st number = x 2 nd number = x + 1 Equation…..x + x + 1 = 415 x + x + 1 = 415 2x + 1 = = - 1 2x = x = 207 The 1 st number is 207 and the 2 nd number is 208.

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Answers to Station #4 Word Problems The sum of three consecutive numbers is 315. Find the numbers. 1 st number = n 2 nd number = n rd number = n + 2 Equation…..n + n n + 2 = 315 n + n n + 2 = 315 3n + 3 = = -3 3n = n = 104 The 1 st number is 104, the 2 nd number is 105, and the 3 rd number is 106. The sum of four consecutive numbers is 230. What are the numbers? 1 st number = x 2 nd number = x rd number = x th number = x + 3 Equation…..x + x x x + 3 = 230 x + x x x + 3 = 230 4x + 6 = = -6 4x = x = 56 The 1 st number is 56, the 2 nd number is 57, the 3 rd number is 58, and the 4 th number is 59.

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Answers to Station #5 Word Problems An equal number of nickels, dimes, and quarters has a value of $4.40. How many of each coin are there. x = number of each coin.05x +.10x +.25x = $ x = $ x = 11 There are a total of 11 nickels, 11 dimes, and 11 quarters. 11 x.05 = x.10 = x.25 = 2.75 $4.40 A collection of 16 coins is valued at $.58. There are four more nickels than dimes and six more pennies than dimes. How many of each coin are there? dimes = d nickels = d + 4 pennies = d + 6 Equation = d + d d + 6 = 16 d + d d + 6 = 16 3d + 10 = = d = d = 2 There are 2 dimes, 6 nickels and 8 pennies.

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Answers to Station #6 Word Problems A rectangle has a length that is 8 meters less than 6 times the width. The perimeter is 460 meters. What is the length and width? width = w length = 6w – 8 Equation…..2w + 2(6w – 8) = 460 2w + 2(6w – 8) = 460 2w + 12w – 16 = w – 16 = = w = w = 34 The width of the rectangle is 34 meters and the length of the rectangle is 196 meters. A landowner wants to fence a triangular parcel of land. One side is twice the second; the third side is 40 meters less than 3 times the second side. The perimeter of the parcel is 320 meters. What is the length of each side? 1 st side = s 2 nd side = 2s 3 rd side = 3(2s) – 40 Equation…..s +2s +3(2s) – 40 = 320 s + 2s + 3(2s) – 40 = 320 s + 2s + 6s – 40 = 320 9s – 40 = = +40 9s = s = 40 The 1 st side is 40m, the 2 nd side is 80m and the 3 rd side is 200m.

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Answers to Bean Salad #1 and #2 Three Bean Salad #1 contains the same number of red beans as lima beans and three more black-eyed peas than red beans. There are a total of 18 beans. What is the number of each type of bean? red beans = r lima beans = r black-eyed peas = r + 3 r + r + r + 3 = 18 3r + 3 = = -3 3r = r = 5 There are 5 red beans, 5 lima beans, and 8 black-eyed peas. Three Bean Salad #2 contains three times as many red beans as black- eyed peas and one more lima bean than red beans. There are eight beans in all. What is the number of each type of bean? black-eyed peas = b red beans = 3b lima bean = 3b + 1 b + 3b + 3b + 1 = 8 7b + 1 = 8 -1 = -1 7b = b = 1 There are 3 red beans, 4 lima beans, and 1 black-eyed pea.

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Answers to Station #7 Word Problems Three Bean Salad #2 contains….. Three times as many red beans as black- eyed peas; and One more lima bean than red beans. There are eight beans in all. What is the number of each type of bean? What is there were 50 beans in this mixture? red beans = 3b lima beans = 3b + 1 black-eyed peas = b 3b + 3b b = 8 7b + 1 = = - 1 7b = b = 1 There are 3 red beans, 4 lima beans, and 1 black-eyed peas. 3b + 3b b = 50 7b + 1 = = -1 7b = b = 7 There are 21 red beans, 22 lima beans, and 7 black-eyed pea.

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