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Published byKyra Stanwood Modified over 4 years ago

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Multiply By Two Digits

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Let’s Review Factors- Numbers multiplied together Product- The answer in a multiplication equation

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Two Digit Multiplication 26 x12 The first step is to make sure the place values are lined up. OnesTens

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Two Digit Multiplication 26 x12 Begin with multiplying the bottom factor’s one’s place with the top factors one’s place. Think, 2 x 6 equals 12. Because there is still the tens place to multiply, you must carry the 1. 2 1

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Two Digit Multiplication 26 x12 Next, multiply the 2 and the other 2. Then, remember to add your carry of 1. Think, 2x2=4+1=5 2 1 5

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Two Digit Multiplication 26 x12 Next, because we are going to the next place value (tens), we need to use a 0 for a place holder. Place the 0 under the 2 in the products line. Erase your carry from before. 2 1 5 0

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Two Digit Multiplication 26 x12 Next, begin to multiply the 1in the tens place with the top line factor. Think 1x6=6. 25 06

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Two Digit Multiplication 26 x12 Think 1x2=2. 25 062

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Two Digit Multiplication 26 x12 Finally, add the two product lines to find the final product. 25 062+ 213 1 Add the ones place. Carry if necessary. Add the tens place. Carry is necessary. Add the hundreds place. Carry if necessary.

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The product is 312

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34 x 19 34 x 19 1. 656 2. 646 3. 677 4. No of these

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Two Digit Multiplication 34 x19 60 0 43 + 646 3 3

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54 x 23 54 x 23 1. 1,242 2. 1,244 3. 1,342 4. 1,142

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Two Digit Multiplication 54 x23 26 0 8 10 + 242 1 1 1

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41 x 18 41 x 18 1. 748 2. 778 3. 738 4. 728

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Two Digit Multiplication 41 x18 82 0 1 4 + 837 3

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68 x 35 68 x 35 1. 2,370 2. 2,345 3. 3,270 4. 2,380

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Two Digit Multiplication 68 x35 04 0 4 20 + 083 4 3 2 2

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76 x 52 76 x 52 1. 3,952 2. 4,952 3. 3,852 4. 3,552

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Two Digit Multiplication 76 x52 25 0 0 38 + 259 1 1 3 3

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94 x 76 94 x 76 1. 7,044 2. 7,144 3. 6,044 4. 6,244

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Two Digit Multiplication 94 x76 46 0 8 65 + 441 2 5 7 2

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Slide 1Fig 25-CO, p.762. Slide 2Fig 25-1, p.765 Slide 3Fig 25-2, p.765.

Slide 1Fig 25-CO, p.762. Slide 2Fig 25-1, p.765 Slide 3Fig 25-2, p.765.

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