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STOICHIAWESOME!! Catalyst How many grams are there in 2.3 moles of dihydrogen monoxide? How many moles are there in 325 grams of Strontium? *If you accidentally took one of the orange calculators yesterday, please return it!

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A little bit of both Problems involving mass (Grams) and number of particles (atoms/molecules) need to use 2 conversion factors ___g Y =___atoms Y ___atoms Y =___g Y

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Practice You have 13 min to do the back of the homework sheet. Your goal is to make sure that EVERY group member can set up the following problems on their own. I will be walking around quizzing members of each group on how to make the correct conversion factors Gram-atoms worksheet When everybody in your group can complete the problems, finish the worksheet from yesterday

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Lets kick this into real life… Us chemists use equations This is where it gets fun!

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S molar Ratio Smore Equation: How do you make a S more? 2 GC + 1 M + 2 C 1 Smore GC= Graham cracker, M= marshmallow, C= chocolate pieces

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2 GC + 1 M + 2 C 1 Smore What does this mean? For every 2 graham crackers, how many smores do we produce? If we had 6 pieces of chocolates, how many smores could we make? If we had 6 marshmallows, how many smores could we make?

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Its the same thing with reactions… Key Point #1: You must BALANCE the equation in stoichometric problems FIRST. Then, what to what. Otherwise, youll never get the right answer

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Stoich-i-ncredible Balanced Equation: Coefficents = Moles __ Al + __ O 2 --> __ Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? First we have to balance the eq. FIRST STEP???

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S molar Ratio Balanced Equation: Coefficents = Moles 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? SECOND STEP??? Mol O 2 Mol Al 2 O 3

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Follow this to success Box the two compounds you are dealing with. The others do not matter for that problem! 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? The only way to move from one compound to another in a conversion is through a mole-to-mole ratio.

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S molar Ratio Balanced Equation: Coefficents = Moles 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? THIRD STEP??? 9 mol O 2

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S molar Ratio Balanced Equation: Coefficents = Moles 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? 9 mol O 2 mol Al 2 O 3 mol O 2 WHAT IS THE CONVERSION FACTOR???!?!?!?!?!?

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S molar Ratio Balanced Equation: Coefficents = Moles 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? 9 mol O 2 2 mol Al 2 O 3 3 mol O 2

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S molar Ratio Balanced Equation: Coefficents = Moles 4 Al + 3 O 2 --> 2 Al 2 O 3 If we have 9 mols of O 2, how many moles of Al 2 O 3 would form? 9 mol O 2 2 mol Al 2 O 3 6 mol Al 2 O 3 3 mol O 2

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Your Turn! Balanced Equation: Coefficents = Moles __Co + __ F 2 --> __CoF 3 How many moles of CoF 3 are produced when 1.25 mol Co reacts?

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Your Turn! Balanced Equation: Coefficents = Moles __ S 8 + __ O 2 --> __ SO 2 If we start with 2.5 mol S 8 how many moles of SO 2 will form?

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Your turn-10 mins Do the first 2 problems on todays worksheet. Make sure everyone in your group can do the problems! Help each other out! If you are truly a chemistry G, you will figure out the next two.

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Can you step it up?? Balanced Equation: Coefficents = Moles __ KCl + __ O 2 --> __ KClO 3 How many moles of KClO 3 will form if we start With 64 grams of O 2 ?

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STEP IT UP!! Balanced Equation: Coefficents = Moles 2 KCl + 3 O 2 --> 2 KClO 3 How many moles of KClO 3 will form if we start With 64 grams of O 2 ? 64 g O 2

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Exit Question Consider the reaction: Cu + AgNO 3 Ag + Cu(NO 3 ) 2 If 12 moles of copper undergoes this reaction, how many grams of Silver will be produced? Dont forget to BALANCE!

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Exit Question

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Chapter 9: Stoichiometry. Composition Stoichiometry Deals with the mass relationships of elements in compounds We did this in Chapter 3 Converting.

Chapter 9: Stoichiometry. Composition Stoichiometry Deals with the mass relationships of elements in compounds We did this in Chapter 3 Converting.

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