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**JEOPARDY! JEOPARDY! Board Instructions**

Template by Kevin Dufendach Updates at JEOPARDY! JEOPARDY! Instructions Board not in any way endorsed or affiliated with the Jeopardy Game Show

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**Import from Excel Template (Template available online)**

Reset Instructions To start a new game, click the “reset” button on the board slide. This will reset the board, set each player’s score to 0, and randomly move the Daily Double. Click “Adj Scores” from the board to manually change scores. Click on the lights at the bottom of question slides to start a 5-second countdown. Incorrect response: Click the “incorrect” button if the player responds incorrectly, and their score will subtract. Correct response: Press the “correct” button if the player responds correctly, and the correct response will then be shown. To skip viewing the correct response, check the box below If no one gets the question correct, press the arrow to go to the next slide (or return to the board if the checkbox below is checked). Troubleshooting: Do not delete the value shape (e.g. $400) from any slide. If you don’t like it, you can move it off the screen, but DON’T DELETE IT, and don’t change its text!!! Do not delete question slides and copy them in from somewhere else. You can do this to replace “answer” slides, but just not question slides (unless you re-apply the hyperlinks to the board) If none of the functions are working, see “Macro Troubleshooting” Import from Excel Template (Template available online) Template by Kevin Dufendach. Updates at Please send questions and comments to

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**Macro Troubleshooting**

If you’re having trouble getting this PowerPoint to work, be sure to “Enable Macros” when opening the file. If you don’t see this box when you open PowerPoint, your security settings may be set too high. In this case, go to the “Tools” menu and select “Options.” Click on [Macro Security…] and then select “Medium.” Press OK until you return to the show. Now save this file and then re-open it. You should now receive the dialog shown above. Click “Enable Macros” Note: some of the functions may not work with versions of PowerPoint other than PowerPoint That’s the only version I’ve tested it on. I’m sure it won’t work on PowerPoint for Mac 2008.

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**Move to reveal location**

The Daily Double is located at: Move to reveal location E4 Instructions Adj Scores Reset Final Board Transforma- tions Radical Functions Polynomial Functions Trig 1 Trig 2 Trig 3 $100 $100 $100 $100 $100 $100 $200 $200 $200 $200 $200 $200 $300 $300 $300 $300 $300 $300 $400 $400 $400 $400 $400 $400 $500 $500 $500 $500 $500 $500

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$100 This is the equation after y = f(x) has been translated 4 units up and 5 units left

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**Transformations, $100 response**

f (x + 5) + 4

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$200 This type of transformation occurs when y is replaced with 3y in the equation y = f(x)

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**Transformations, $200 response**

Vertical compression by a factor of

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$300 If the domain of y = f(x) is x ≤ 3, then this is the domain of y = f (x + 10) - 2

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**Transformations, $300 response**

x ≤ -7

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$400 This is the equation of y = f(x) after it has underdone a vertical translation up 5, a vertical reflection, a vertical translation down 2, and then a vertical expansion by a factor of 3

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**Transformations, $400 response**

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$500 If y = f(x) has a range of -3 ≤ y ≤ 2, then this is the range of y = |f(x) -1|?

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**Transformations, $500 response**

0 ≤ y ≤ 4

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$100 This is the domain of

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**Radical Fcn’s, $100 response**

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$200 This is the equation of the radical function with an endpoint of (4, -3) and an x-intercept of (-12,0).

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**Radical Fcn’s, $200 response**

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$300 This is the graph of

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**Radical Fcn’s, $300 response**

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$400 Solve

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**Radical Fcn’s, $400 response**

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$500 If (8, -6) is on the graph of y=f(x), then this point is on the graph of

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**Radical Fcn’s, $500 response**

(-9, 9)

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**This is the end behaviour of the graph**

$100 This is the end behaviour of the graph

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**Polynomial Fcn’s, $100 response**

Quadrants 2 to 4

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**This is the remainder when is divided by x - 2**

$200 This is the remainder when is divided by x - 2

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**Polynomial Fcn’s, $200 response**

57

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**then this is the value of k**

$300 If x + 5 is a factor of then this is the value of k

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**Polynomial Fcn’s, $300 response**

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**This is the equation of the cubic function in general form with**

$400 This is the equation of the cubic function in general form with x-intercepts of and a y-intercept of 2

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**Polynomial Fcn’s, $400 response**

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**This is the multiplicity of the x-intercept at 2 in the function**

$500 This is the multiplicity of the x-intercept at 2 in the function

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**Polynomial Fcn’s, $500 response**

3

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**radians is this many degrees**

$100 radians is this many degrees

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**Trigonometry 1, $100 response**

660˚

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**This is the exact value of**

$200 This is the exact value of

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**Trigonometry 1, $200 response**

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**This is the radius if an arc length of 8 cm subtends an angle of 34˚**

$300 This is the radius if an arc length of 8 cm subtends an angle of 34˚

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**Trigonometry 1, $300 response**

13.48 cm

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$400 This is the period of

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**Trigonometry 1, $400 response**

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$500 Point P is the intersection of the terminal arm of angle θ in standard position and the unit circle with centre (0, 0). If P is in quadrant 3 and sin θ = a, determine the coordinates of P in terms of a

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**Trigonometry 1, $500 response**

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**This is the minimum value of the function y = -4cosx + 1.5**

$100 This is the minimum value of the function y = -4cosx + 1.5

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**Trigonometry 2, $100 response**

-2.5

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**This is the phase shift of the function**

$200 This is the phase shift of the function

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**Trigonometry 2, $200 response**

3π to the left

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**This is the general term for the asymptotes of**

$300 This is the general term for the asymptotes of

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**Trigonometry 2, $300 response**

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$400 If the equation h = 2.5sin 0.6(t – 4) is used to estimate the height of tides at the beach, this is the number of times in one day (t =0 is midnight) that the tide will have a height of 3.5 m

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**Trigonometry 2, $400 response**

4 (3:32am, 9:43am, 2:00pm, 8:11pm) .

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$500 A wheel with diameter 10cm is rolling along the ground. If point P is touching the ground at t = 0, and the wheel rotates once every 12 seconds, this is the equation that represents the height of point P above ground at time t seconds

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**Trigonometry 2, $500 response**

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**This is the restriction for the expression**

$100 This is the restriction for the expression

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**Trigonometry 3, $100 response**

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**Given and the angle terminates in quadrant 3, this is the value of .**

$200 Given and the angle terminates in quadrant 3, this is the value of

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**Trigonometry 3, $200 response**

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$300 Simplify

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**Trigonometry 3, $300 response**

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$400 Does equal to

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**Trigonometry 3, $400 response**

No, it equals to

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$500 Solve

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**Trigonometry 3, $500 response**

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DAILY DOUBLE Enter your wager: $ Go!

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**Final Jeopardy Category**

More Trig! Final Jeopardy Reveal Prompt Reveal Response

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**Final Jeopardy Response**

Incorrect Correct Incorrect Correct Incorrect Correct Incorrect Correct Final Jeopardy Response This is the sum of

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Final Jeopardy Answer -1

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