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High School Part 2 /2 by SSL Technologies Physics Ex-49 Click The mirror equation is a geometrical derivation for solving problems with curved mirrors.

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Presentation on theme: "High School Part 2 /2 by SSL Technologies Physics Ex-49 Click The mirror equation is a geometrical derivation for solving problems with curved mirrors."— Presentation transcript:

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2 High School Part 2 /2 by SSL Technologies

3 Physics Ex-49 Click The mirror equation is a geometrical derivation for solving problems with curved mirrors. Where:f = focal length (in metres) d o = Object distance (in metres) d i = Image distance (in metres) Where: M = magnification factor (no units) h i = height of image (in metres) h o = height of object (in metres) and PART-2 /2

4 Physics Ex-49 Click Be sure to observe the following sign conventions when using the mirror formula:  All distances are measured from the vertex of a curved mirror.  Distances of objects and real images are positive.  Distances of virtual images are negative.  Object and image heights are positive when upright and negative when inverted. Parabolic mirrors are used as reflectors for searchlights, flashlights, projectors and automobile headlights. Where:f = focal length (in metres) d o = Object distance (in metres) d i = Image distance (in metres) PART-2

5 Physics Ex-49 Click When M is less than 1, the image is reduced. When M is negative, the image is inverted.

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7 Physics Ex-49 Type (real or virtual) : _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ Question-1 An object is 60 cm from a converging mirror whose radius of curvature is 30 cm. Determine the characteristics of the image. Click Real Click 20 cm (in front of mirror) - 0.33 (inverted and smaller than object) Inverted

8 Physics Ex-49 Type (real or virtual) : _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ Question-2 An object is 25 cm from a concave mirror whose focal length is 15 cm. Determine the characteristics of the image. Click Real Click 37.5 cm (in front of mirror) - 1.5 (inverted and larger than object) Inverted

9 Physics Ex-49 Type (real or virtual) : _______________ Location: _______________ Magnification: _______________ Attitude (upright/inverted): _______________ Question-3 An object is placed 7.5 cm from a concave mirror that has a focal length of 15 cm. Determine the characteristics of the image. Click Virtual Click 15 cm (behind mirror) 2 (upright and larger than object) Upright Negative sign indicates virtual image

10 Physics Ex-49 Question-4 A converging mirror has a focal length of 15 cm. Where would you place an object in front of this mirror in order to produce an upright, virtual image, twice as tall as the object? Click Negative sign indicates virtual image

11 Physics Ex-49 This means a virtual image (d i is negative). Question-5 What is the focal length of a concave mirror when an object that is placed 2 cm in front of the mirror produces an image that is seen 5 cm behind the mirror? Click

12 Physics Ex-49 Question-6 A concave mirror has a focal length of 30 cm. A square object, 4 cm per edge, is situated with its center 10 cm in front of the mirror. Determine: Click a) The position (center) of the image.

13 Physics Ex-49 Question-6 A concave mirror has a focal length of 30 cm. A square object, 4 cm per edge, is situated with its center 10 cm in front of the mirror. Determine: Click b) The area of the image.

14 Physics Ex-49 Question-7 Illustrated below is an object situated in front of a convex mirror. Graphically, find the image and state its characteristics.. Click The image is virtual, upright, reduced and located behind the mirror. NOTE Convex mirrors always produce images that are virtual, upright and reduced.

15 Physics Ex-49 Question-8 An object is placed 10 cm in front of a convex mirror whose focal length is 15 cm. Determine the characteristics of the image. Click The image is virtual (since d i is negative), upright (since M is positive), smaller than the object (since M = 0.6) and located behind the mirror. Click d i

16 Physics Ex-49 Question-9 When an object is 30 cm in front of a concave mirror, its image is real and situated 15 cm from the mirror. Determine the location of the image when the object is placed 6.0 cm from the mirror. Click The image is virtual and located behind mirror.

17 Physics Ex-49 Question-10 Fill in the four (4) missing quantities in the table below: Click MIRROR TYPE FOCAL LENGTH OBJECT DISTANCE IMAGE DISTANCE OBJECT HEIGHT IMAGE HEIGHT Concave4 cm-12 cm2 cm Convex10 cm-7 cm1 cm 3 cm8 cm -23.3 cm0.7 cm 1 2 34

18 Physics Ex-49 Question-11 An object is placed in front of a convex mirror as illustrated below. Draw and label the light rays necessary to locate the image. Incident ray Reflected ray Extended ray Incident ray Reflected ray Extended ray Image Click Image is virtual, upright and reduced.

19 Physics Ex-49 A) 10.0 cm B) 20.0 cm C) 60.0 cm D) 90.0 cm E) 120.0 cm Question-12 An object 45.0 cm high is placed in front of a convex mirror whose focal length is 30.0 cm. If a virtual image 15.0 cm high is formed, determine the distance the object is from the mirror. Click Step-2 Calculate d o Given Step-1 Calculate d i REMINDER Convex mirrors have a negative focal length. Virtual images have a negative distance.

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