# EOC REVIEW FLASH POWER POINT Gregory Fisher, Mt. Tabor High School Used byJeffrey Williams, West Forsyth High School.

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EOC REVIEW FLASH POWER POINT Gregory Fisher, Mt. Tabor High School Used byJeffrey Williams, West Forsyth High School

Hidden Parenthesis 5 2x or 6 -1/2 … ( ) … 5a 2 b when a is -2 and b is 3/4 … 5(-2) 2 (3/4)

A candidate receives 56% within a 4% margin of error |x – 56 |< 4 |x -.56|<.04 … |x – Middle#| < othernumber

Center and Radius of (x-3) 2 +(y+6) 2 =4 Center: (3,-6) Radius: = 2 …

X 2 + y 2 – 6x +10y – 2 = 0 (x 2 – 6x ) +(y 2 + 10y ) =2 (x – 3) 2 + 9 (y + 5) 2 1/2 square +25 1/2 square =36 Center: (3, -5) Radius: =6 … +

3 x(11 – 2x) (13 – 2x) = 60 Solve by graphing and look for smallest x An open box is made from 11 x 13 sheet of paper. Find dimensions to make a volume of 60in 3 if minimum waste An open box is made from 8 x 10 sheet of paper. Find dimensions to make maximum volume. x(8 – 2x) (10 – 2x) = y Find by graphing. Give x value x(length – 2x)(width – 2x)=V …

Town of 100,000 grows 5.4% for 7 years 100000(1 +.054) 7 or (1.054) 7 … \$20,000 car depreciates 13.2% for 4 years 20000(1 -.132) 4 or (.868) 4 … …

Growth rate of 5(1.036) x 3.6% {1.036-1 =.036 = 3.6%} Growth rate of 7(.84) x -16% {.84 - 1 = -.16 = -16% or depreciates 16%} … ……

Translating 3|x-2|+ 1 Narrow because 3>1 Right 2 x-2=0  x= 2 Up 1 … Translating from Fatter 5  1 Left 6 (right 4 to left 2) Up 6 (down 3 to up 3) … …

Abs. value of a increases Abs. value of a decreases b increasesb decreases c increasesc decreases Thinner Wider Right Left UpDown …

Write log 3 x>2 in exponential form x> 3 2 Write 5 x =y in logrithmic form x= log 5 y The bottom number remains the bottom and the other two switch sides ………

Typing log 2 x + log 3 9 into calculator … Writing 3log x 2 + 1/2 log x y – 5 log x z as one log … … Log x 2 3 + log 2 y 1/2 – log x z 5 … …

X varies directly as the square of m x = km 2 p varies jointly as n, cube of q, and inversely as w n = n varies inversely as the square root of m P=knq 3 … … … w

f(x) = x 2 – 6x g(x) = x – 3 =(x-3) 2 – 6(x-3) =(x-3)(x-3) – 6(x-3) =x 2 –3x–3x+9–6x+18 Find f(g(x)) or f o g(x) =x 2 –12x+27 Find g o f(-3) … f(-3) = (-3) 2 – 6(-3) = 27 g(27) = (27) – 3 = 24

f(x)=5x – 2. Find f -1 (x) Inverse x + 2=5y x=5y – 2 (switch x and y and solve for y) y=5x – 2 (1/5) x + (2/5) =y or f -1 (x)= Or look at table of original graph and find (0,-2), (1,3) and then look for (-2,0) and (3,1) on table of answers …

Vertical Asymptotes Holes Horizontal Asymptotes # has graph of & error on table Always x= … Error on table but NO on graph Set TABLE to 10000 and look at y values. (E-07 is 0) Always Y= … … …

Regression Steps 1.Turn diagnostic on: 2 nd. Scroll to DiagnosticON ENTER 2.STAT EDIT put the numbers in. 3. STAT  Choose Regression Linreg for Lines Quadreg for Quadratics Expreg for Exponential (Look for r 2 to be closest to 1) 4. Write down equation on paper. 5. Input equation into y= 6. Look at the table

Solve: x + 2y = 12 2x = 13 + 7y x + 2y = 12 2x – 7y= 13 [A] -1 [B] (10,1) x=10, y=1 -7y to the left side …

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