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Determination of an Angle || A B C D MP ON Given triangles ∆ABC and ∆ADC, having AB=AC=AD in a square □ MNOP. Line N C = C O, and BD is parallel to NO. What is the value of BCD?

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical.

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical. ∆ABC and ∆ADC are isosceles.

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical. ∆ABC and ∆ADC are isosceles. ∆ABD is equilateral.

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical. ∆ABC and ∆ADC are isosceles. ∆ABD is equilateral. 60°

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical. ∆ABC and ∆ADC are isosceles. ∆ABD is equilateral. 60° 30° 75°

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Determination of an Angle || A B C D MP ON Triangles ∆ABC and ∆ADC are Identical. ∆ABC and ∆ADC are isosceles. ∆ABD is equilateral. 60° 30° 75° BCD = 150°

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EXAMPLE 1 Standardized Test Practice SOLUTION Let ( x 1, y 1 ) = ( –3, 5) and ( x 2, y 2 ) = ( 4, – 1 ). = (4 – (–3)) 2 + (– 1 – 5) 2 = 49 + 36 = 85 (

EXAMPLE 1 Standardized Test Practice SOLUTION Let ( x 1, y 1 ) = ( –3, 5) and ( x 2, y 2 ) = ( 4, – 1 ). = (4 – (–3)) 2 + (– 1 – 5) 2 = 49 + 36 = 85 (

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