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# Do Now 1. If f(x) = │(x² – 50)│, what is the value of f(-5) ?

## Presentation on theme: "Do Now 1. If f(x) = │(x² – 50)│, what is the value of f(-5) ?"— Presentation transcript:

Do Now 1. If f(x) = │(x² – 50)│, what is the value of f(-5) ?
A B C. 0 D E. -75 2. ( √2 - √3 )² = A √6 B. 5 - √6 C √6 D. 1 - √2 E. 1 = A B C D E. 226

P.3 Lines in the Plane SWBAT 1. Find the slope of a line.
2. Write linear equations given points on lines and their slopes. 3. Use slope-intercept forms of linear equations to graph lines. 4. Use slope to identify parallel and perpendicular lines.

The slope of a line Slope: rise over run, the change in y over the change in x

The slope of a line Finding slope given 2 points:
1. (-2, 0) and (3, 1) 2. (-1, 2) and (2, 2) 3. (3, 4) and (3, 1)

The point-slope form of a line
Point-slope form: y – y1 = m(x – x1) Find an equation of the line that passes through the point (1, -2) and has a slope of 3. Find an equation of the line that passes through (2, - 3) and (4, 5).

Using point-slope to create linear models
During 1997, Barnes and Noble’s net sales were \$2.8 billion, and in 1998 net sales were \$3.0 billion. 1. Write a linear equation giving the net sales y in terms of the year x. 2. Use the equation to estimate the net sales during

Linear extrapolation: an approximation in which the estimated point lies outside of the given points
Linear interpolation: the estimated point lies between the two given points

Sketching graphs of lines
Slope-intercept form: y = mx + b Better suited to graph linear equations

Sketching graphs of lines
Determine the slope and y-intercept of each linear equation and describe its graph. 1. x + y = 2 2. y = 2

Parallel Lines Parallel lines: have slopes that are equal
Find the slope-intercept form of the equation of the line that passes through the point (2, -1) and is parallel to the line 2x – 3y = 5.

Perpendicular Lines Perpendicular lines: have slopes that are negative reciprocals Find an equation of the line that passes through the point (2, -1) and is perpendicular to the line x – 3y = 5.

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