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Published byNathan Foster Modified over 2 years ago

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By: Alex Tam, Jon Coley, Patrick Phillips, and Rabee Kaheel 2 nd Period, Mrs. Culbreth February 24,06

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16 Feet 60° 54ft 60 ° Triangle x Tan(60)= x/16 16*tan(60)=x/16* ft=X = 32.7 ft=X Long Leg= (3)(short Leg) X= (3)(16) X=27.7 ft. (163) X= X=32.7 ft

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45° TRIANGLE Tan(45)=X/28 28*tan(45)=X/28*28 28=X = 33.5 feet=X Leg=leg 28= = 33.5 feet=X 45° 28feet X 5.58

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30° TRIANGLE Tan(30)=X/48 48*Tan(30)=X/48* =X = 33.5 ft=X Long leg=(3)short leg (48)=(3)X (48)/(3)=(3)X/(3) 27.7=X (483/3) = 33.5 ft.=X 48 Feet 30° X 5.83 Ft.

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50° Triangle Tan(50)=X/24 24*tan(50)=X/24* =X = 33.6 ft=X 24 Feet 50° X 54

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CONCLUSION We concluded that the average stature of the light pole is 33.3feet. We have also concluded that no matter what the angle of elevation and the distance from the object was, you would still have the same stature measure. Trig functions and triangle formulas were used to determine the heights of the objects.

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