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LR #5 If equal masses are used, then hydrogen will be in excess. Although there are twice as many moles of hydrogen as carbon monoxide, because its molar mass is much smaller, there will be many more molecules of hydrogen present than carbon monoxide. If you want mathematical proof, pick a random value for the mass of carbon monoxide and hydrogen (remember they are the same) and perform the stoichiometry. You will see there is much more hydrogen.

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1 mole KClO3 X 2KClO3 2KCl + 3O g KClO3 X 3 moles O2

1 mole KClO3 X 2KClO3 2KCl + 3O g KClO3 X 3 moles O2

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