Download presentation

Presentation is loading. Please wait.

Published byMina Wardlow Modified over 2 years ago

1
Working out Ks from solubility

2
What is the Ks for CaCO 3 (s) when s(CaCO 3 (s))= 5.01 x mol L -1 ? Write the equation for the solid at equilibrium with water CaCO 3 (s) Ca 2+ + CO 3 2- Work out the concentrations of the aqueous ions. If the solubility of CaCO 3 (s)= 5.01 x mol L -1 [Ca 2+ ] = 5.01 x mol L -1 [CO 3 2- ] = 5.01 x mol L -1

3
Write the Ks expression. Remember do not include water or solids into the expression. Ks = [Ca 2+ ] [CO 3 2- ] Substitute the numerical values for [Ca 2+ ] and [CO 3 2- ] into the expression. Ks = [5.01 x ] [5.01 x ] Ks = [2.51 x ]

4
What is the Ks for Ag 2 S(s) 1.26 x moles of Ag 2 S(s) dissolves in 1 litre of water? Write the equation for the solid at equilibrium with water Ag 2 S(s) 2Ag + + S 2- Work out the concentrations of the aqueous ions. If the solubility of Ag 2 S(s)= 1.26 x mol L -1 [Ag + ] = 2 x s(Ag 2 S) = 1.26 x mol L -1 [S 2- ] = s(Ag2S) = 2.52 x mol L -1

5
Write the Ks expression. Remember do not include water or solids into the expression. Ks = [Ag + ] 2 [S 2- ] Substitute the numerical values for [Ag + ] and [S 2- ] into the expression. Ks = [2.52 x ] 2 [1.26 x ] Ks = [8.00 x ]

6

Similar presentations

© 2016 SlidePlayer.com Inc.

All rights reserved.

Ads by Google