Download presentation

Presentation is loading. Please wait.

Published byMarshall Chaplain Modified over 3 years ago

1
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: 1.) 320 2.) 51 3.) 8500 4.) 9.3 5.) 970 6.) 6.9 7.) 11 8.) 28000

2
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 51 3.) 8500 4.) 9.3 5.) 970 6.) 6.9 7.) 11 8.) 28000

3
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 8500 4.) 9.3 5.) 970 6.) 6.9 7.) 11 8.) 28000

4
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.3 5.) 970 6.) 6.9 7.) 11 8.) 28000

5
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.39.259.35 5.) 970 6.) 6.9 7.) 11 8.) 28000

6
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.39.259.35 5.) 970965975 6.) 6.9 7.) 11 8.) 28000

7
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.39.259.35 5.) 970965975 6.) 6.96.856.95 7.) 11 8.) 28000

8
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.39.259.35 5.) 970965975 6.) 6.96.856.95 7.) 1110.511.5 8.) 28000

9
Starter: Recap finding upper and lower boundaries Write the upper and lower boundaries of the following values which are written to 2 s.f: Lower boundUpper bound 1.) 320315325 2.) 5150.551.5 3.) 850084508550 4.) 9.39.259.35 5.) 970965975 6.) 6.96.856.95 7.) 1110.511.5 8.) 280002750028500

10
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area?

11
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? L L WW

12
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W L L WW

13
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW

14
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55

15
Objective: Use upper and lower boundaries to answer practical questions To get answers using boundaries For maximum answerFor minimum answer When multiplying:u/bound X u/boundl/bound X l/bound When dividing:u/bound l/boundl/bound u/bound When adding:u/bound + u/boundl/bound + l/bound When subtracting:u/bound – l/boundl/bound – u/bound

16
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55

17
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55 Max perimeter = (2 x 6.85) + (2 x 7.55) = 28.8m

18
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55 Max perimeter = (2 x 6.85) + (2 x 7.55) = 28.8m Min perimeter = (2 x 6.75) + (2 x 7.45) = 28.4m

19
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55 Max perimeter = (2 x 6.85) + (2 x 7.55) = 28.8m Min perimeter = (2 x 6.75) + (2 x 7.45) = 28.4m Max area = 6.85 x 7.55 = 51.7 to 1 d.p

20
Objective: Use upper and lower boundaries to answer practical questions Example A rectangular garden has sides of length 6.8m and 7.5m measured to 1d.p. 1.) What are the minimum and maximum values of the perimeter? 2.) What are the minimum and maximum values of the area? Perimeter = 2L + 2W Area = LW L L WW L/boundU/bound 6.86.756.85 7.57.457.55 Max perimeter = (2 x 6.85) + (2 x 7.55) = 28.8m Min perimeter = (2 x 6.75) + (2 x 7.45) = 28.4m Max area = 6.85 x 7.55 = 51.7 to 1 d.p Min area = 6.75 x 7.45 = 50.3 to 1 d.p

Similar presentations

Presentation is loading. Please wait....

OK

Números.

Números.

© 2017 SlidePlayer.com Inc.

All rights reserved.

Ads by Google

Ppt on age of exploration Ppt on magic garden Ppt on recycling waste materials Ppt on power sharing in democracy it's your vote Ppt on sound navigation and ranging systematic Ppt on natural numbers vs whole numbers Ppt on nuclear family and joint family Ppt on project life cycle Ppt on data handling for class 11 Ppt on components of railway track