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PROJECTION OF PLANES. PROJECTIONS OF PLANES In this topic various plane figures are the objects. What will be given in the problem? 1.Description of the.

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Presentation on theme: "PROJECTION OF PLANES. PROJECTIONS OF PLANES In this topic various plane figures are the objects. What will be given in the problem? 1.Description of the."— Presentation transcript:

1 PROJECTION OF PLANES

2 PROJECTIONS OF PLANES In this topic various plane figures are the objects. What will be given in the problem? 1.Description of the plane figure. 2.Its position with HP and VP. In which manner its position with HP & VP will be described? 1. Inclination of its SURFACE with one of the reference planes will be given. 2. Inclination of one of its EDGES with other reference plane will be given (Hence this will be a case of an object inclined to both reference Planes.) To draw their projections means F.V, T.V. & S.V. What is usually asked in the problem? Study the illustration showing surface & side inclination given on next page.

3 HP a1a1 b1b1 c1c1 d1d1 VP a d c b a d cb For Fv For Tv For F.V. For T.V. For F.V. HP a bc d a 1 d 1 c 1 b 1 HP a1a1 b1b1 c1c1 d1d1 CASE OF A RECTANGLE – OBSERVE AND NOTE ALL STEPS. SURFACE PARALLEL TO HP PICTORIAL PRESENTATION SURFACE INCLINED TO HP PICTORIAL PRESENTATION ONE SMALL SIDE INCLINED TO VP PICTORIAL PRESENTATION ORTHOGRAPHIC TV-True Shape FV- Line // to xy ORTHOGRAPHIC FV- Inclined to XY TV- Reduced Shape ORTHOGRAPHIC FV- Apparent Shape TV-Previous Shape ABC

4 PROCEDURE OF SOLVING THE PROBLEM: IN THREE STEPS EACH PROBLEM CAN BE SOLVED :( As Shown In Previous Illustration ) STEP 1. Assume suitable conditions & draw Fv & Tv of initial position. STEP 2. Now consider surface inclination & draw 2 nd Fv & Tv. STEP 3. After this,consider side/edge inclination and draw 3 rd ( final) Fv & Tv. ASSUMPTIONS FOR INITIAL POSITION: (Initial Position means assuming surface // to HP or VP) 1.If in problem surface is inclined to HP – assume it // HP Or If surface is inclined to VP – assume it // to VP 2. Now if surface is assumed // to HP- Its TV will show True Shape. And If surface is assumed // to VP – Its FV will show True Shape. 3. Hence begin with drawing TV or FV as True Shape. 4. While drawing this True Shape – keep one side/edge ( which is making inclination) perpendicular to xy line ( similar to pair no. on previous page illustration ). A B Now Complete STEP 2. By making surface inclined to the resp plane & project its other view. (Ref. 2 nd pair on previous page illustration ) C Now Complete STEP 3. By making side inclined to the resp plane & project its other view. (Ref. 3 nd pair on previous page illustration )

5 x y p q r s t u u(p) t(q) s(r) 1.I u t s r q P P(u) q(t) r(s) 1.II K.M.KumarEG2111 Engineering Graphics

6 xy 1.III q r(p) s(u) t p(u) q(t) r(s) p q r s t u u(p) t(q) s(r) u 1 (p 1 ) t 1 (q 1 ) s 1 (r 1 ) 30° q1q1 r1r1 s1s1 t1t1 u1u1 p1p1 1.IV K.M.KumarEG2111 Engineering Graphics

7 1.V xy u t s r q P P(u) q(t) r(s) 30° P 1 (u 1 ) q 1 (t 1 ) r 1 (s 1 ) q 1 r 1 s 1 t 1 u 1 p 1 K.M.KumarEG2111 Engineering Graphics

8 Problem No.4.A circular lamina of diameter 60 mm is held vertical with its surface inclined at 45° to the VP. Its centre is 40 mm above the HP and 30 mm in front of the VP. Draw its top and front views. xy (8) 3(7) 4(6) ° (8 1 ) 3 1 (7 1 ) 4 1 (6 1 ) 5 1 O o K.M.KumarEG2111 Engineering Graphics

9 Problem No.5.A square lamina PQRS of side 40 mm rests on the ground on its corner P in such a way that the diagonal PR is inclined at 45° to the HP and apparently inclined at 30° to the VP. Draw its Projections. xy p q r s p q(s) r 45° p 1 q 1 (s 1 ) r 1 p1p1 s1s1 r1r1 q1q1 p2p2 q2q2 s2s2 r2r2 q 2 r 2 s 2 p 2 30° K.M.KumarEG2111 Engineering Graphics

10 Problem No.6.A circular plate of diameter 70 mm has the end P of the diameter PQ in the HP and the plate is inclined at 40° to the HP. Draw its projections when the diameter PQ appears to be inclined at 45° to the VP in the top view. xy s q r p p r(s) q 40° p 1 r 1 (s 1 ) q 1 p1p1 q1q1 r1r1 s1s1 45° q2q2 p2p2 r2r2 s2s2 p 2 r 2 q 2 s 2

11 Problem No.7.A rectangular plate 70 x 40 mm has one of its shorter edges in the VP inclined at 40° to the HP. Draw its top view if its front view is a square of side 40 mm. xy p q rs p(s) q(r) p 1 s 1 r 1 q 1 p 1 (s 1 ) q 1 (r 1 ) 40° p 2 q 2 r 2 s 2 s2s2 p2p2 q2q2 r2r2 K.M.KumarEG2111 Engineering Graphics

12 Problem No.8.A hexagonal plate of side 20 mm rests on the HP on one of its sides inclined at 45° to the VP. The surface of the plate makes an angle of 30° with the HP. Draw the front and top views of the plate. p q r s t u u(p) t(q) s(r) 30° q1q1 r1r1 s1s1 t1t1 u1u1 p1p1 xy u 1 (p 1 ) t 1 (q 1 ) s 1 (r 1 ) p2p2 u2u2 t2t2 s2s2 r2r2 q2q2 u 2 t 2 s 2 r 2 q 2 p 2 45°


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