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**Mass Calculations for Reactions**

Copyright © by Pearson Education, Inc. Publishing as Benjamin Cummings edited by bbg

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**Moles to Grams Suppose we want to determine the mass (g) of NH3**

that can form from 2.50 moles N2. N2(g) + 3H2(g) NH3(g) The plan needed would be moles N moles NH grams NH3 The factors needed would be: mole factor NH3/N2 and the molar mass NH3

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**Moles to Grams The setup for the solution would be:**

2.50 mole N2 x 2 moles NH3 x g NH3 1 mole N mole NH3 given mole-mole factor molar mass = g NH3

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**Learning Check How many grams of O2 are needed to produce**

0.400 mole Fe2O3 in the following reaction? 4Fe(s) O2(g) Fe2O3(s) 1) g O2 2) g O2 3) g O2

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Solution 2) g O2 0.400 mole Fe2O3 x 3 mole O2 x g O2= g O2 2 mole Fe2O mole O2 mole factor molar mass

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**Calculating the Mass of a Reactant**

The reaction between H2 and O2 produces 13.1 g water. How many grams of O2 reacted? 2H2(g) O2(g) 2H2O(g) ? g g The plan and factors would be g H2O mole H2O mole O g O2 molar mole-mole molar mass H2O factor mass O2

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**Calculating the Mass of a Reactant**

The setup would be: 13.1 g H2O x 1 mole H2O x 1 mole O2 x g O g H2O moles H2O 1 mole O2 molar mole-mole molar mass H2O factor mass O2 = g O2

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**Learning Check 2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(g) 1) 88.6 g C2H2**

Acetylene gas C2H2 burns in the oxyacetylene torch for welding. How many grams of C2H2 are burned if the reaction produces 75.0 g CO2? 2C2H2(g) O2(g) CO2(g) + 2H2O(g) 1) g C2H2 2) g C2H2 3) g C2H2

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**Solution 3) 22.2 g C2H2 2C2H2(g) + 5O2(g) 4CO2(g) + 2H2O(g)**

75.0 g CO2 x 1 mole CO2 x 2 moles C2H2 x g C2H2 44.0 g CO moles CO mole C2H2 molar mole-mole molar mass CO factor mass C2H2 = g C2H2

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**Calculating the Mass of Product**

When 18.6 g ethane gas C2H6 burns in oxygen, how many grams of CO2 are produced? 2C2H6(g) O2(g) CO2(g) + 6H2O(g) 18.6 g ? g The plan and factors would be g C2H mole C2H mole CO g CO2 molar mole-mole molar mass C2H factor mass CO2

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**Calculating the Mass of Product**

The setup would be 18.6 g C2H6 x 1 mole C2H6 x 4 moles CO2 x g CO2 30.1 g C2H moles C2H mole CO2 molar mole-mole molar mass C2H factor mass CO2 = g CO2

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Learning Check How many grams H2O are produced when 35.8 g C3H8 react by the following equation? C3H8(g) + 5O2(g) CO2(g) + 4H2O(g) g H2O g H2O g H2O

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**Solution C3H8(g) + 5O2(g) 3CO2(g) + 4H2O(g)**

35.8 g C3H8x 1 mole C3H8 x 4 mole H2O x g H2O 44.1 g C3H mole C3H mole H2O molar mole-mole molar mass C3H factor mass H2O = g H2O (2)

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