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Mechanical Energy Total Mechanical Energy. Total Mechanical Energy (E T ): Energy can be transferred or transformed, never lost Law of Conservation of.

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Presentation on theme: "Mechanical Energy Total Mechanical Energy. Total Mechanical Energy (E T ): Energy can be transferred or transformed, never lost Law of Conservation of."— Presentation transcript:

1 Mechanical Energy Total Mechanical Energy

2 Total Mechanical Energy (E T ): Energy can be transferred or transformed, never lost Law of Conservation of Energy *If friction negligible If friction is not negligible then….

3 A 56kg diver runs & dives from the edge of a cliff into the water which is located 4m below. If she is moving at 8m/s the instant she leaves the cliff, determine the speed at which she enters the water. Before JumpAt Water Level EgEg EkEk EgEg EkEk m = 56 kg g = 9.8 N/kg h = 4 m m = 56 kg v = 8 m/s m = 56 kg g = 9.8 N/kg h = 0 m m = 56 kg v = ? =

4 Before JumpAt Water Level

5 A child throws a 0.2kg rock at a tree. When the rock leaves the childs hand, it is moving at 20m/s & is located 1.5m above the ground. How high above the ground does the rock strike the tree if it is moving at 10m/s at that instant? ThrowTree EgEg EkEk EgEg EkEk m = 0.2 kg g = 9.8 N/kg h = 1.5 m m = 0.2 kg v = 20 m/s m = 0.2 kg g = 9.8 N/kg h = ? m = 0.2 kg v = 10 m/s =

6 ThrowTree

7 A 2 kg ball rolls along a frictionless surface. It passes point C at a speed of 20m/s. What was the speed of the ball at point A? Point APoint C EgEg EkEk EgEg EkEk m = 2 kg g = 9.8 N/kg h = 20 m m = 2 kg v = ? m/s m = 2 kg g = 9.8 N/kg h = 25 m m = 2 kg v = 20m/s = A C 20 m 25 m

8 Point APoint C

9 A force of 16N is applied to a 400g mass, starting at rest, over a distance of 5m. How long does it take the mass to move 5m? BeforeAfter 5m EgEg EkEk EgEg EkEk E g = 0m = 0.4 kg v = 0 m/s E g = 0m = 0.4 kg v = ? Recall, work = energy So work applied to move mass 5m Law of Conservation of Energy

10 Work required to set block in motion

11

12 You are playing with a toy slider track. The top of the hump is 1.2m above the level of the slider at the beginning of the track. The average force of friction between the 0.15kg slider & the track is 0.11N. The distance from point A to point B along the track is 2.3m. You propel the slider by applying a constant force of 6.6N hoping to get it over the hump. How far must you push the slider to ensure that it makes it over the hump?

13 Top: BUT….friction… Recall, work = energy Bottom: Recall, energy= work


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