Presentation on theme: "Prisms Mathematical Definition- A polyhedron with two congruent faces that lie in a parallel plane Prism is composed of a base which is on both sides."— Presentation transcript:
1 PrismsMathematical Definition- A polyhedron with two congruent faces that lie in a parallel planePrism is composed of a base which is on both sides of the object and then lateral facesLateral faces are every face of the prism that are not bases.
3 Faces of a PrismThe highlighted faces of this triangular prism are the bases, while the clear ones are the lateral faces.In this rectangular prism, the highlighted faces are again the base.
4 Surface Area of PrismUsing the net method is one way to find the area.You break the 3-D shape down into easy 2 dimensional shapes.The triangular prism to the right when breaks down into two triangles as the base and three rectangles as the lateral faces.
5 Formula for Surface Area Surface Area = 2(area of base) + (Perimeter of Base)(height)SA= 2(B)+ Ph
7 Examples SA= 2B+Ph B= ½ (4)(6)= 12 cm P= 4+6+7= 17 cm H= 12 cm ==228 cm squared
8 Surface Area of a Cylinder A cylinder has a total of three surfaces: a top, bottom, and middle. The top and bottom, which are circlesTo find the surface area we must separate the cylinder into these parts and find the area of each separately.The first parts are circles (top and bottom of cylinder). The area of a circle is πr^2. So, the area of two circles would be πr^2 + πr2 = 2πr^2.
9 The third surface, the lateral surface area, is the curved wall of the cylinder. We can manipulate the curved wall of a cylinder to produce a recognizable shape.First start with the cylinder and make a cut down the middle as shown in Step One.Next the cut edge will be cut open as shown in Step Two.When the cylinder's wall is completely open, it makes the shape of a rectangle.
10 To calculate the rectangles area, we need to go back to the top of the original cylinder which is a circle. The distance around a circle is called its circumference, C = 2πr. The circumference has been marked in red in the diagram.When the cylinder wall is completely open, we see that the circumference of the circle becomes the length of the final rectangle. The dimensions of the rectangle are the circumference, C = 2πr, and the height of the cylinder, h. So, the area of the rectangle is A = l x w = C x h = 2πr x h = 2πrh.
11 The next step is to put all the surfaces together which include the top the bottom and the walls (middle).Those values are πr^2 + πr^2 + 2πrh = 2πr^2 + 2πrh.This can also be written as SA = 2B + Ph where B=area of base, P=perimeter of base, and h=height
12 Example If r = 6 ft and h = 4 ft then what is the surface area? SA = 2πr^2 + 2πrh= 2(3.14)(6)^2 + 2(3.14)(6)(4)== 376.8If r = 6 ft and h = 4 ft then what is the surface area?
13 Surface Area of a Pyramid Pyramids that have a square base have a total of five surfaces: one base and four sides.
14 The first step in finding the surface area is to find the the slant height value, l. The height of the pyramid is a leg of the right triangle. The base of the right triangle is half the length of the base edge of the pyramid, s. At this point, we would use The Pythagorean Theorem to calculate the slant heighth^2 + (1/2s)^2 = l^2
15 Now find the area of each surface The base is a square with dimensions, s, so its area is s x s = s^2The other four surfaces are triangles with an area of ½(base)(height) or ½(s)(I)½(s)(I) x 4 = 2(s)(l)The total surface area equation iss^2 + 2sl
16 Example Given: s = 8 m and h = 3 m, find the surface area First we calculate the slant height: 3^2 + (½x8)^2 = (I)^2= (l)^2= (I)^2= INext use the formula to calculate the surface area:SA = (s)^2 + 2(s)(l)= (7 in)^2 + 2(7 in)(6.95 in) = 49 in^ in^2 = in^2.
17 Surface Area of Cones Separates into 2 parts: Base and Side Area of Base = r^2Area of Side = (radius of base)(slant height)= r^2 + rS
18 Example First identify your radius of base and slant height Use Pythagorean Theorem to find S12^2 + 5^2 = 13^2r^ rS = (12)^ (12)(13) = 300S12
19 Example 2 Find surface area of the collar Large cone – small cone rs - rs(6)(10) (3)(5)= 45