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**Forces & Motion Momentum: Applied Physics and Chemistry Lecture 6**

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**p = mv v Momentum p m p: momentum (kg ·m/s) m: mass (kg)**

quantity of motion p = mv m p v p: momentum (kg ·m/s) m: mass (kg) v: velocity (m/s)

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**v Momentum p m p = ? p = mv m = 280 kg p = (280 kg)(3.2 m/s)**

Find the momentum of a bumper car if it has a total mass of 280 kg and a velocity of 3.2 m/s. GIVEN: p = ? m = 280 kg v = 3.2 m/s WORK: p = mv p = (280 kg)(3.2 m/s) p = 896 kg·m/s m p v

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**v Momentum p m p = 675 kg·m/s v = p ÷ m m = 300 kg**

The momentum of a second bumper car is 675 kg·m/s. What is its velocity if its total mass is 300 kg? GIVEN: p = 675 kg·m/s m = 300 kg v = ? WORK: v = p ÷ m v = (675 kg·m/s)÷(300 kg) v = 2.25 m/s m p v

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**Conservation of Momentum**

Law of Conservation of Momentum The total momentum in a group of objects doesn’t change unless outside forces act on the objects. pbefore = pafter

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**Conservation of Momentum**

One bumper car has a mass of 300 kg and a velocity of 2 m/s. A second bumper car has a mass of 500 kg and a velocity of 2 m/s. They collide, stick together and move off. What is their velocity after the collision?

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Notes: Chapter 11.3 Newton’s Third Law of Motion and Momentum.

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