Presentation on theme: "Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar."— Presentation transcript:
Thermal Aspects of Cadmium Zinc Telluride (CZT) Imager Presented By M.K. Hingar
Plan Configuration Design Inputs Design of the Detector Board Analysis Results Radiator & Heat Pipe Design Critical Elements Conclusions
Thermal design Inputs for CZT-Imager Power generated by each channel of CZT ASIC 3 mW Number of channels in each CZT Module 256 Power generated by each CZT Module 768 mW Number of CZT in each quadrant 16 Power generated by each quadrant 12.3 W Number of quadrants 4 Power generated by the CZT-Imager 49.2 W Allowed temperature variation among CZTs of each quadrant 5o5o Allowed temperature difference among quadrants 5o5o Working temperature range of the Instrument 0 o to – 20 o
CZT DETECTORCZT DETECTOR BOARD WITHIN CZT DETECTOR BOARD HEAT PIPERADIATOR 5 o 4 o 5o5o 5 o TEMPERATURE DIFFERENCE BETWEEN DIFFERENT STAGES IN ONE QUADRANT Thermal Analysis has five Steps: Transfer of heat from CZT Detector to the CZT Detector Board. Transfer of heat within the CZT Detector Board. Transfer of heat from CZT Detector Board to the Heat pipes. Transfer of heat from Heat pipes to Radiator. Radiator design.
Transfer of heat from CZT Detector to the CZT Detector Board q = k A ΔT Where q = Power = 0.780 W, k = Thermal Conductivity of thermal epoxy = 0.08 W / cm 2 o K A = Area = 4 cm 2 ΔT = 0.78 / (0.08 * 4) = 2.42 o K If we consider factor of safety 2, it may be about 5 o K.
Design of Detector Board Cu-In-Cu Copper Coating
PROPERTIES OF CIC LAMINATE Metal /Core/ MetalDensity (g/cm 3 ) Coefficient of Thermal Expansion (ppm/ 0 c) Thermal Conductance W/m- 0 c Modulus elasticity, GPa Tensile strength, MPa x, yz z 20Cu/60In/20Cu8.456.07.716422135310-412 12.5Cu/75In/12.5Cu8.313.65.311064140380-472
Transfer of heat within the CZT Detector Board The Detector Board of 20Cu/60In/20Cu. The thickness of Detector Board is 3mm. The preliminary analysis give the maximum temperature on the Detector Board of the quadrant is about 4 o.
Boundary Conditions Temperature at the edges of Detector Board is 0 o CZT Power (780 mW) distributed equally in 20mm X 20mm area
Analysis shows Heat Drain from two opposite sides of the Detector Board is necessary. Radiation losses not considered.
STEPSTEMPERATURE DIFFERENCE Transfer of heat from CZT to the Detector Board 5 o Within Detector Board 4 o Detector Board to heat pipe 5 o Heat Pipe to Radiator 5 o
Implications of quadrants failures for thermal design Suppose one of the quadrants fails then radiator will dissipate about 37 W (50 W ), the Radiator will have temperature of - 27 o ( - 20 o ). Suppose two of the quadrants fail then radiator will dissipate about 25 W (50 W), the Radiator will have temperature of - 40 o ( - 20 o ). Possible use of heaters to be considered after final simulation.
CONCLUSIONS Total temperature difference is within 15 o to 20 o. Procuring one Detector Board and measure temperature difference.