Download presentation

Presentation is loading. Please wait.

Published bySteven Nolan Modified over 5 years ago

2
Topic: Equations Objectives: To solve linear equations with the unknown on one side or two sides. (Level 5/6) Keywords: equation, unknown, operation, inverse, balance, solve Thursday, 14 November 2013

3
Mental Algebra Starter You have 10 seconds for each question (1 – 10)

4
1 3a +5a

5
2 3b + 2 + 2b + 4

6
25y – 11y 3

7
17c + 2c – 5c 4

8
If d = 3, what is 4d? 5

9
If e = -3, what is 2e? 6

10
If t = 2, what is 4(t+1)? 7

11
If x = 5, what is 4(x-1)? 8

12
If d = 3, evaluate 5d+1 9

13
2y=6 What is y? 10

14
Answers 1) 8a6) -6 2) 5b + 67) 12 3) 14y8) 16 4) 14c9) 16 5) 1210) 3

15
Great job!

16
If I add 7 to a number I get 18. What is my number? My number is 11

17
Together 2 bags of sweets contain 40 sweets. How many sweets in each bag? Each bag contains 20 sweets

18
Ali will be 21 years old, in 8 years time. How old is Ali? Ali is 13 years old

20
Equations – Success if you can do these 3x = 6 x/4 = 2 x + 3 = 17 x – 4 = 13 3x + 4 = 25 4x – 3 = 17

21
© T Madas n + 5 = 12 n +5 12 –5 7 n = 7

22
If I add 7 to a number I get 18. What is my number? n = 18 n +7 18 –7 11 n = 11 My number is 11 + 7

23
Together 2 bags of sweets contain 40 sweets. How many sweets in each bag? 2b2b = 40 b x2x2 40 ÷2÷2 20 b = 20 Each bag contains 20 sweets

24
Ali will be 21 years old, in 8 years time. How old is Ali? a = 21 a +8+8 21 – 8 13 a = 13 Ali is 13 years old + 8 Age now

25
How to solve the x + 3 = 10 type of equation

26
You get rid of the + 3 by - 3 But you must subtract 3 from both sides x + 3 =10 x + 3 – 3 = 10 - 3 x = 7

27
For equations like x + 3 = 10 just subtract 3 from both sides x + 3 = 10 x = 10 - 3 x = 7 Like this

28
How to solve the x – 3 = 7 type of equation

29
You get rid of the – 3 by + 3 But you must to add 3 to both sides x – 3 = 7 x – 3 + 3 = 7 + 3 x = 10

30
For equations like x – 3 = 7 just add 3 to both sides x – 3 = 7 x – 3 + 3 = 7 + 3 x =10 Like this

31
How to solve the 5x = 20 type of equation

32
5 x = 20 means 5 X x = 20 5 x = 20 5 X x = 20

33
5 x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 5 x = 20 5 X x ÷ 5 = 20 ÷ 5

34
5 x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 5 x = 20 5 X x ÷ 5 = 20 ÷ 5 x = 4

35
5 x = 20 means 5 X x = 20 So, you get rid of the 5 X by ÷ 5 But you must divide both sides by 5 5 x = 20 5 X x ÷ 5 = 20 ÷ 5 x = 4

36
For equations like 5x = 20 just divide both sides by the number that multiplies the x. 5x = 20 x = 20 ÷ 5 x = 4 Like this

37
How to solve the x/3 = 4 type of equation

38
x /3 = 4 x ÷ 3 = 4 It means x ÷ 3 = 4

39
x /3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 Get rid of ÷ 3 by using a X 3 It means x ÷ 3 = 4

40
x /3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 Get rid of ÷ 3 by using a X 3 It means x ÷ 3 = 4

41
x /3 = 4 x ÷ 3 = 4 x ÷ 3 X 3 = 4 X 3 x = 12 Get rid of ÷ 3 by using a X 3 You must X 3 on both sides It means x ÷ 3 = 4

42
For equations like x/3 = 4 just multiply both sides by the number that divides the x. x/3 = 4 x = 4 X 3 x =12 Like this

43
Remember, always do the same thing to both sides. Felix is checking that you do this properly. x/3 = 12 x ÷ 3 X 3 = 12 X 3 x =36

44
If I double my house number and then subtract 4, I get 18. What is my house number? 2n2n = 18– 4 n x2x2 18 +4 11 – 4 22 ÷2÷2 n = 11 I live at number 11

45
Cassie has 5 stamps. She bought another three books of stamps and now has 23 stamps. How many stamps in each book? 5 = 23 + 3b 3b + 5 = 23 b x3x3 23 –5–5 6 +5+5 18 ÷3÷3 b = 6 Each book contains 6 stamps

46
Plenary: Evaluating your own progress Now go over your work, taking note of the mistakes and errors that you made. At what Level would you assess yourself ? Describe something that you have learned. Do you feel you have met the objectives of the lesson? Write one sentence to describe your progress in this lesson.

47
Great job!

Similar presentations

Presentation is loading. Please wait....

OK

My Alphabet Book abcdefghijklm nopqrstuvwxyz.

My Alphabet Book abcdefghijklm nopqrstuvwxyz.

© 2018 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google