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**Circle Drawing Asst. Prof. Dr. Ahmet Sayar Kocaeli University**

Computer Engineering Advanced Computer Graphics Spring 2012

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Properties of Circle A circle is a set of points that are all at a given distance r from a center position ( xc , yc ). For any circle point ( x , y ), this distance relationship is expressed by the Pythagorean theorem in Cartesian coordinates as We could use this equation to calculate the position of points on a circle circumference by stepping along the x axis in unit steps from xc - r to xc + r and calculating the corresponding y values at each position as

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**A Simple Circle Drawing Algorithm**

The equation for a circle is: where r is the radius of the circle So, we can write a simple circle drawing algorithm by solving the equation for y at unit x intervals using:

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Brute Force Method Computational cost: floating point multiplications, subtraction, square-root, rounding

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**Issues on Brute Force Method**

Problems in the brute force method Involves considerable computations at each steps. Lots of float-point calculations Spacing between plotted pixel positions is not uniform Eliminating unequal spacing Expressing the circle equation in parametric polar form x= xc+ r cos(alpha), y= yc+ r sin(alpha) for 0o < alpha < 360o For a more continuous boundary, set the step size at 1/r Reducing computation cost Considering the symmetry of circles Still require a good deal of computation time for a octant

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Common approach However, unsurprisingly this is not a brilliant solution! Firstly, the resulting circle has large gaps where the slope approaches the vertical Secondly, the calculations are not very efficient The square (multiply) operations The square root operation – try really hard to avoid these! We need a more efficient, more accurate solution

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**Midpoint Circle Algorithm (1/4)**

Only need to draw the arc between (0, r) and (r/sqrt(2),r/sqrt(2)) The coordinates of the other pixels can be implied from the 8-way symmetry rule. 45o

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Eight-Way Symmetry The first thing we can notice to make our circle drawing algorithm more efficient is that circles centred at (0, 0) have eight-way symmetry (x, y) (y, x) (y, -x) (x, -y) (-x, -y) (-y, -x) (-x, y)

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**Mid-Point Circle Algorithm**

Similarly to the case with lines, there is an incremental algorithm for drawing circles – the mid-point circle algorithm In the mid-point circle algorithm we use eight-way symmetry so only ever calculate the points for the top right eighth of a circle, and then use symmetry to get the rest of the points

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**Midpoint Circle Algorithm**

Choose E as the next pixel if M lies inside the circle, and SE otherwise. d = d<0: Select E dnew = d + (2xp+3) d>0: Select SE dnew = d + (2xp–2yp+5) y-1/2 M SE d xp xp+1 r2 = x2+y2 d= F(x,y) = x2+y2-r2

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**Choosing the Next Pixel**

decision variable d M (x, y) (x+1, y) (x+1, y-1) E SE choose SE choose E

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**Change of d when E is chosen**

Mold (x, y) (x+1, y) (x+1, y-1) E SE (x+2, y) (x+2, y-1) Mnew

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**Change of d when SE is chosen**

(x, y) (x+1, y) E Mold SE Mnew (x+1, y-2) (x+2, y-2)

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**Initial value of d (0,R) (1,R) M0 (1,R-1)**

Remember f(x+1,y+1/2) when we talked about midpoint line drawing M0 (1,R-1)

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**Midpoint Circle Algorithm (3/4)**

Start with P (x = 0, y = R). x = 0; y = R; d = 5/4 – R; /* real */ While (x < y) { If (d >= 0) // SE is chosen y = y – 1 d = d + 2 * (x – y) + 5 else // E is chosen d = d + 2 * x + 3 x = x+1; WritePixel(x, y) } Where is the arch drawn?

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New Decision Variable Our circle algorithm requires arithmetic with real numbers. Let’s create a new decision variable kd kd=d-1/4 Substitute kd+1/4 for d in the code. Note kd > -1/4 can be replaced with h > 0 since kd will always have an integer value.

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**Midpoint Circle Algorithm**

Start with P (x = 0, y = R). x = 0; y = R; kd = 1 – R; While (x < y) { If (kd >= 0) // SE is chosen y = y – 1 kd = kd + 2 * (x – y) + 5 else // E is chosen kd = kd + 2 * x + 3 x = x+1; WritePixel(x, y) }

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**LINE DRAWING with Midpoint Algorithm**

x=xL y=yL d=xH - xL c=yL - yH sum=2c+d //initial value // decision param sum is multiplied with 2, act val (c+d/2) draw(x,y) while ( x < xH) // iterate until reaching the end point if ( sum < 0 ) // below the line and choose NE sum += 2d y++ x++ sum += 2c Compare this with the algorithm presented in the previous slide EXPLAIN !

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**Initial value of decision param: sum**

What about starting value? (xL+1,yL+1/2) is on the line! Sum = 2c + d

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**Drawing circle in OpenGL**

OpenGL does not have any primitives for drawing curves or circles. However we can approximate a circle using a triangle fan like this: glBegin(GL_TRIANGLE_FAN) glVertex2f(x1, y1) for angle# = 0 to 360 step 5 glVertex2f(x1 + sind(angle#) * radius#, y1 + cosd(angle#) * radius#) next glEnd()

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**If you want to use mid-point to draw circle**

If you calculate the points on circle through the given mid-point algorithm, then use glBegin(GL_POINTS) glVertex2f(x1, y1) glEnd()

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